A number of people _____at the street corner. A: A.are B: B.am C: C.Is D: D.be
A number of people _____at the street corner. A: A.are B: B.am C: C.Is D: D.be
2.My pen is rather old, but it is all right for me to . A: A.write B: B.write with C: C.be written D: D.be written with
2.My pen is rather old, but it is all right for me to . A: A.write B: B.write with C: C.be written D: D.be written with
【单选题】6. ________wear seat belt when you drive a car. A.Make sure of B.Make sure that C.Be sure to D.Be sure that A. Make sure of B. .Make sure that C. Be sure to D. Be sure that
【单选题】6. ________wear seat belt when you drive a car. A.Make sure of B.Make sure that C.Be sure to D.Be sure that A. Make sure of B. .Make sure that C. Be sure to D. Be sure that
【单选题】下列哪个小调为 g小调的关系大调() A.bB大调 B.B大调 C.E大调 D.bE大调 A. bB大调 B. B大调 C. E大调 D. bE大调
【单选题】下列哪个小调为 g小调的关系大调() A.bB大调 B.B大调 C.E大调 D.bE大调 A. bB大调 B. B大调 C. E大调 D. bE大调
Li,Be,B原子失去一个电子所需要的能量相差不大,但最难失去第二个电子的原子是[br][/br]A.B[br][/br]B.都相同[br][/br]C.Li[br][/br]D.Be
Li,Be,B原子失去一个电子所需要的能量相差不大,但最难失去第二个电子的原子是[br][/br]A.B[br][/br]B.都相同[br][/br]C.Li[br][/br]D.Be
如果ξ与η不相关,则()。 A: D(ξ+η)=Dξ+Dη B: D(ξ-η)=Dξ-Dη C: D(ξη)=Dξ·Dη D: E(ξη)=Dξ·Dη
如果ξ与η不相关,则()。 A: D(ξ+η)=Dξ+Dη B: D(ξ-η)=Dξ-Dη C: D(ξη)=Dξ·Dη D: E(ξη)=Dξ·Dη
已有定义intd=-2;,执行以下语句后的输出结果是:printf('*d(1)=%d*d(2)=%3d*d(3)=%-3d* ',d,d,d,d);printf('*d(4)=%o*d(5)=%7o*d(6)=%-7o* ',d,d,d,d);printf('*d(4)=%x*d(5)=%6x*d(6)=%-6x* ',d,d,d,d);
已有定义intd=-2;,执行以下语句后的输出结果是:printf('*d(1)=%d*d(2)=%3d*d(3)=%-3d* ',d,d,d,d);printf('*d(4)=%o*d(5)=%7o*d(6)=%-7o* ',d,d,d,d);printf('*d(4)=%x*d(5)=%6x*d(6)=%-6x* ',d,d,d,d);
圆柱螺旋弹簧的旋绕比C是() A: d/D B: d/D C: D/d D: D/d
圆柱螺旋弹簧的旋绕比C是() A: d/D B: d/D C: D/d D: D/d
已有定义int d= –2;执行以下语句后的输出结果是。 printf(" * d(1) =%d * d(2)= %3d * d(3) =% –3d * ",d,d,d); printf(" * d(4) =%d * d(5)= %7d * d(6) =% –7d * ",d,d,d);
已有定义int d= –2;执行以下语句后的输出结果是。 printf(" * d(1) =%d * d(2)= %3d * d(3) =% –3d * ",d,d,d); printf(" * d(4) =%d * d(5)= %7d * d(6) =% –7d * ",d,d,d);
若有说明语句:int a,b,c,* d=&c;,则能正确从键盘读入三个整数分别赋给变量a、b、d的语句是 ( ) A.scanf("%d%d%d",&a,&b,d); B.scanf("%d%d%d",&a,&b,&d); C.scanf("%d %d%d",a,b,d); D.scanf("%d%d%d",a,b,* d);
若有说明语句:int a,b,c,* d=&c;,则能正确从键盘读入三个整数分别赋给变量a、b、d的语句是 ( ) A.scanf("%d%d%d",&a,&b,d); B.scanf("%d%d%d",&a,&b,&d); C.scanf("%d %d%d",a,b,d); D.scanf("%d%d%d",a,b,* d);