写出下面程序的运行结果：[br][/br] private class Person6 { var lastName: String = "zhang" var no: Int = 100 var heiht: Float = 145.4f } fun main(args: Array[String]) { var Person1: Person6 = Person6() Person1.lastName = "wang" println("lastName:${Person1.lastName}") Person1.no = 9 println("no:${Person1.no}") Person1.no = 20 println("no:${Person1.no}") }

1. The person in dialogue 1 wants to go to the _______________.2. The person in dialogue 2 wants to go to the ______.3. The person in dialogue 3 wants to go to the ______________________.

1. The person in dialogue 1 wants to go to the _______________.

（6-2）定义如下Person类，(1)处合理的代码是。 class Person { String name, department; int age; public Person(String n) { name = n; } public Person(String n, int a) { name = n; age = a; } public Person(String n, int a, String d) { ① department = d; } }

12. There are _________ （1 word）ages in a person’s existence according to Shakespeare.

1、With an older person you generally shake hands and smile, of course.

【多选题】定义了如下Person类,下面()程序段能够正确初始化Person数组。 class Person{ private String name; public Person(String name){ this.name=name; } } A. Person [ ] list=new Person[ ]{new Person("孙悟空"),new Person("猪八戒")}; B. Person list[ ]=new Person[ ]{new Person("孙悟空"),new Person("猪八戒")}; C. Person[ ]  list={new Person("孙悟空"),new Person("猪八戒")}; D. Person  list=new Person[ ]{new Person("孙悟空"),new Person("猪八戒")};

（6-9）定义Person类（属性有姓名，年龄)，完成如下任务： （1）在Test类中定义方法Boolean contains(Person[]per，Person temp),该方法判断Person数组是否有Person对象temp，如果数组中存在与per相同的Person对象返回boolean； （2）定义showPerson(Person[] per)输出Person对象数组所有元素； （3）对上面定义的方法进行测试

Which pattern of comparison do you find in the following outlines? Person A 1) family background 2) educational background 3) working experience Person B 1) family background 2) educational background 3) working experience

The man wants ______. A: a patient person B: a friendly person C: a careful person D: a handsome person