在0~4π 区间绘制y=5cos(10t+π/3)关系曲线,下述哪个程序正确? A: t=0:4*pi, y=5cos(10t+pi/3) B: t=0:0.1:4π, y=5*cos(10*t+π/3) C: t=0:4π, y=5*cos(10*t+π/3) D: t=0:0.1:4*pi, y=5*cos(10*t+pi/3)
在0~4π 区间绘制y=5cos(10t+π/3)关系曲线,下述哪个程序正确? A: t=0:4*pi, y=5cos(10t+pi/3) B: t=0:0.1:4π, y=5*cos(10*t+π/3) C: t=0:4π, y=5*cos(10*t+π/3) D: t=0:0.1:4*pi, y=5*cos(10*t+pi/3)
上限是4/π,下限是0,求∫(cosθ)^-3dθ
上限是4/π,下限是0,求∫(cosθ)^-3dθ
∫cos^4tdt,积分上限是π/4,下限是0,
∫cos^4tdt,积分上限是π/4,下限是0,
自然光通过透振方向互相垂直的两块偏振片,入射光强度为I<sub>0</sub>,若第三块偏振片插入起偏器和检偏器之间,且它的透振方向和竖直方向成θ角,试问透射光的强度为[ ] A: (I<sub>0</sub>sin<sup>2</sup>2θ)/8 B: I<sub>0</sub>cosθ C: I<sub>0</sub>cos<sup>4</sup>θ D: I<sub>0</sub>cos<sup>2</sup>θ
自然光通过透振方向互相垂直的两块偏振片,入射光强度为I<sub>0</sub>,若第三块偏振片插入起偏器和检偏器之间,且它的透振方向和竖直方向成θ角,试问透射光的强度为[ ] A: (I<sub>0</sub>sin<sup>2</sup>2θ)/8 B: I<sub>0</sub>cosθ C: I<sub>0</sub>cos<sup>4</sup>θ D: I<sub>0</sub>cos<sup>2</sup>θ
设角θ是第四象限角,则() A: cosθ>0,且tanθ>0 B: cosθ<0,且tanθ>0 C: cosθ<0,且tanθ<0 D: cosθ>0,且tanθ<0
设角θ是第四象限角,则() A: cosθ>0,且tanθ>0 B: cosθ<0,且tanθ>0 C: cosθ<0,且tanθ<0 D: cosθ>0,且tanθ<0
已知\( y = {x^3}\cos 2x \),则\( y'' \)为( ). A: 0 B: \( 6x\cos 2x{\rm{ + }}12{x^2}\sin 2x - 4{x^3}\cos 2x \) C: \( 6x\cos 2x - 12{x^2}\sin 2x{\rm{ + }}4{x^3}\cos 2x \) D: \( 6x\cos 2x - 12{x^2}\sin 2x - 4{x^3}\cos 2x \)
已知\( y = {x^3}\cos 2x \),则\( y'' \)为( ). A: 0 B: \( 6x\cos 2x{\rm{ + }}12{x^2}\sin 2x - 4{x^3}\cos 2x \) C: \( 6x\cos 2x - 12{x^2}\sin 2x{\rm{ + }}4{x^3}\cos 2x \) D: \( 6x\cos 2x - 12{x^2}\sin 2x - 4{x^3}\cos 2x \)
已知sinα+sinβ+sinγ=0,cosα+cosβ-cosγ=0,则cos(α-β)的值是[ ]
已知sinα+sinβ+sinγ=0,cosα+cosβ-cosγ=0,则cos(α-β)的值是[ ]
Which two pairings match the application with the correct Cos value?() A: CoS 0 = Best-Effort Data B: CoS 1 = Best-Effort Data C: CoS 3 = High Priority D: CoS 4 = High Priority Data E: CoS 5 = Voice Bearer F: CoS 7 = Voice Bearer
Which two pairings match the application with the correct Cos value?() A: CoS 0 = Best-Effort Data B: CoS 1 = Best-Effort Data C: CoS 3 = High Priority D: CoS 4 = High Priority Data E: CoS 5 = Voice Bearer F: CoS 7 = Voice Bearer
下面哪个矩阵不是\(2\)阶酉矩阵? A: \(\begin{pmatrix}e^i\cos{\theta}&e^i\sin{\theta}\\-e^i\sin{\theta}&e^i\cos{\theta}\end{pmatrix}\) B: \(\begin{pmatrix}\cos{\theta}&\sin{\theta}\\-\sin{\theta}&\cos{\theta}\end{pmatrix}\) C: \(\begin{pmatrix}1&0\\0&1\end{pmatrix}\) D: \(\begin{pmatrix}e^i\cos{\theta}&e^i\sin{\theta}\\e^{-i}\sin{\theta}&e^i\cos{\theta}\end{pmatrix}\)
下面哪个矩阵不是\(2\)阶酉矩阵? A: \(\begin{pmatrix}e^i\cos{\theta}&e^i\sin{\theta}\\-e^i\sin{\theta}&e^i\cos{\theta}\end{pmatrix}\) B: \(\begin{pmatrix}\cos{\theta}&\sin{\theta}\\-\sin{\theta}&\cos{\theta}\end{pmatrix}\) C: \(\begin{pmatrix}1&0\\0&1\end{pmatrix}\) D: \(\begin{pmatrix}e^i\cos{\theta}&e^i\sin{\theta}\\e^{-i}\sin{\theta}&e^i\cos{\theta}\end{pmatrix}\)
中国大学MOOC: 写出下面程序执行后的运行结果。#include <stdio.h>int main(){int i,j,a[4][4];for(i=0;i<4;i++)for(j=0;j<4;j++) a[i][j]=1+i-j;for(i=0;i<4;i++) {for(j=0;j<4;j++)if(a[i][j]>0) printf("%3d",a[i][j]);putchar(\n);} return 0;}
中国大学MOOC: 写出下面程序执行后的运行结果。#include <stdio.h>int main(){int i,j,a[4][4];for(i=0;i<4;i++)for(j=0;j<4;j++) a[i][j]=1+i-j;for(i=0;i<4;i++) {for(j=0;j<4;j++)if(a[i][j]>0) printf("%3d",a[i][j]);putchar(\n);} return 0;}