The project _________ by the end of 2020, will expand the city’s telephone network to cover 1,000,000 users.

1.Suppose you deposit $10,000 in an account in the beginning of 2020. If the account earns 4%, how much will be in the account at the end of 2020?

The European Union is one of China's key trading partners. With Brexit taking place at the end of 2020, the EU still has 28 members left.

The European Union is one of China's key trading partners. With the Brexit taking place at the end of 2020, the EU still has 28 members left.

The European Union is one of China's key trading partners. With Brexit taking place at the end of 2020, the EU still has 28 members left. A: 正确 B: 错误

下面代码的执行结果是： ls = [“2020”, “2020”, “Python”] ls.append(2020) ls.append([2020, “2020”]) print(ls): [‘2020’, ‘2020’, ‘Python’, 2020, 2020, ‘2020’]|[‘2020’, ‘2020’, ‘Python’, 2020, [2020, ‘2020’]]|[‘2020’, ‘2020’, ‘Python’, 2020, [‘2020’]]|[‘2020’, ‘2020’, ‘Python’, 2020]

下面代码的执行结果是‪‬‪‬‪‬‪‬‪‬‮‬‫‬‭‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‪‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‪‬‪‬( )‪‬‪‬‪‬‪‬‪‬‮‬‫‬‭‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‪‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‪‬‪‬ ‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬。ls = ["2020", "20.20", "Python"] ls.append(2020)ls.append([2020, "2020"])print(ls) A: ['2020', '20.20', 'Python', 2020, 2020, '2020'] B: ['2020', '20.20', 'Python', 2020, [2020, '2020']] C: ['2020', '20.20', 'Python', 2020] D: ['2020', '20.20', 'Python', 2020, ['2020']]

下面代码的执行结果是：‪‪‪‪‪‪‫‪‪‪‪‪‪‫‪‪‪‪‪‫‪‪‪‪‪‫‪‪‪‪‪‪‫‪‪‪‪‪‪‫ ls = ["2020", "20.20", "Python"] ls.append(2020) ls.append([2020, "2020"]) print(ls) A: ['2020', '20.20', 'Python', 2020, ['2020']] B: ['2020', '20.20', 'Python', 2020, 2020, '2020'] C: ['2020', '20.20', 'Python', 2020] D: ['2020', '20.20', 'Python', 2020, [2020, '2020']]

以下代码的输出结果是______。ls = ["2020", "20.20", "Python"]ls.append(2020)ls.append([2020, "2020"])print(ls) A: ['2020', '20.20', 'Python', 2020] B: ['2020', '20.20', 'Python', 2020, [2020, '2020']] C: ['2020', '20.20', 'Python', 2020, 2020, '2020'] D: ['2020', '20.20', 'Python', 2020, ['2020']]

下面代码的执行结果是：（ ）ls= [“2020”, “20.20”, “Python”]ls.append(2020)ls.append([2020, “2020”])print(ls) A: [‘2020’, ‘20.20’, ‘Python’, 2020] B: [‘2020’, ‘20.20’, ‘Python’, 2020, [2020, ‘2020’]] C: [‘2020’, ‘20.20’, ‘Python’, 2020, [‘2020’]] D: [‘2020’, ‘20.20’, ‘Python’, 2020, 2020, ‘2020’]r