count = 0 while count < 5: print (count, " 小于 5") count = count + 1 else: print (count, " 大于或等于 5")

下列哪条语句是正确的?_______________ A: int count = 5; int* x = &count; B: int count = 5; int x = &count; C: int count = 5; int& x = &count; D: int count = 5; int** x = &count;

下列程序的运行结果是（   ）。 count = 0 while count < 5: print(count, " is less than 5") count = count + 1 else: print(count, " is not less than 5")

count = 0while count &lt; 5： print（ count） count = count + 2print( “Over!")

请阅读下面的程序: count = 0 while count < 5: print(count, '小于5') if count == 2: break count += 1 else: print(count, "不小于5") 关于上述程序的说法中,描述错误的是

48. 以下Java代码片段编译运行的结果是。 int &#91;&#93; a = {1,2,3,4,5}; for (int count = 0 ; count<5; count ++) System.out.print(a&#91;count++&#93;) int &#91;&#93; a = {1,2,3,4,5}; for (int count = 0 ; count<5; count ++) System.out.print(a&#91;count++&#93;)

若COUNT(A1:A3)=2,则COUNT(A1:A3,3)=5

下面的代码段执行之后count的值是什么( ) int count = 1; for(int i = 1; i <= 5; i++) { count+= i; } System.out.println(count); int count = 1; for(int i = 1; i <= 5; i++) { count+= i; } System.out.println(count);

执行下述代码: count = 5 def print_num(): count = 2 count += 1 print(count) 当调用print_num()函数时,输出结果为( )

1.从严格意义上讲，下列的程序表示的是一个算法吗？为什么？Count = 0while(Count != 5):Count = Count + 2