计算:x^2-y^2/x^2-9y^2+(x-2y)^2/9y^2-x^2+5y^2-4xy/x^2-9y^2
计算:x^2-y^2/x^2-9y^2+(x-2y)^2/9y^2-x^2+5y^2-4xy/x^2-9y^2
已知|x+1|=4,(y+2)2=4,且xy>0,则x-y=()。
已知|x+1|=4,(y+2)2=4,且xy>0,则x-y=()。
函数f(xy,)=xy在条件x+y=1下的极大值为()。 A: 1/4 B: 1/2 C: 1 D: 2
函数f(xy,)=xy在条件x+y=1下的极大值为()。 A: 1/4 B: 1/2 C: 1 D: 2
分解因式()x()3()y()-()2()x()2()y()2()+()xy()3()正确的是A.()xy()(()x()+()y())()2()B.()xy()(()x()2()﹣()2()xy()+()y()2())()C.()xy()(()x()2()+2()xy()﹣()y()2())()D.()xy()(()x()﹣()y())()2
分解因式()x()3()y()-()2()x()2()y()2()+()xy()3()正确的是A.()xy()(()x()+()y())()2()B.()xy()(()x()2()﹣()2()xy()+()y()2())()C.()xy()(()x()2()+2()xy()﹣()y()2())()D.()xy()(()x()﹣()y())()2
9. 已知函数$z=z(x,y)$由${{z}^{3}}-3xyz={{a}^{3}}$确定,则$\frac{{{\partial }^{2}}z}{\partial x\partial y}=$( ) A: $\frac{z({{z}^{4}}-2xy{{z}^{2}}-{{x}^{2}}{{y}^{2}})}{{{({{z}^{2}}-xy)}^{3}}}$ B: $\frac{z({{z}^{4}}-2xy{{z}^{2}}-xy)}{{{({{z}^{2}}-xy)}^{2}}}$ C: $\frac{z({{z}^{3}}-2xyz-{{x}^{2}}{{y}^{2}})}{{{({{z}^{2}}-xy)}^{3}}}$ D: $\frac{z({{z}^{3}}-2xy{{z}^{2}}-{{x}^{2}}y)}{{{({{z}^{2}}-xy)}^{3}}}$
9. 已知函数$z=z(x,y)$由${{z}^{3}}-3xyz={{a}^{3}}$确定,则$\frac{{{\partial }^{2}}z}{\partial x\partial y}=$( ) A: $\frac{z({{z}^{4}}-2xy{{z}^{2}}-{{x}^{2}}{{y}^{2}})}{{{({{z}^{2}}-xy)}^{3}}}$ B: $\frac{z({{z}^{4}}-2xy{{z}^{2}}-xy)}{{{({{z}^{2}}-xy)}^{2}}}$ C: $\frac{z({{z}^{3}}-2xyz-{{x}^{2}}{{y}^{2}})}{{{({{z}^{2}}-xy)}^{3}}}$ D: $\frac{z({{z}^{3}}-2xy{{z}^{2}}-{{x}^{2}}y)}{{{({{z}^{2}}-xy)}^{3}}}$
设(X,Y)的联合密度为[img=246x61]17de89815546a18.png[/img],则EY=_____, E(XY)=_____. A: EY=4/5, E(XY)=7/5 B: EY=7/5, E(XY)=2/5 C: EY=3/5, E(XY)=1/2 D: EY=2/3, E(XY)=2/5
设(X,Y)的联合密度为[img=246x61]17de89815546a18.png[/img],则EY=_____, E(XY)=_____. A: EY=4/5, E(XY)=7/5 B: EY=7/5, E(XY)=2/5 C: EY=3/5, E(XY)=1/2 D: EY=2/3, E(XY)=2/5
已知x+y=6且xy=4,则(x-y)2=();x4+y4=().
已知x+y=6且xy=4,则(x-y)2=();x4+y4=().
以下程序的输出结果是:()ab = 4def myab(ab, xy): ab= pow(ab,xy) print(ab,end=" ")myab(ab,2)print( ab) A: 4 4 B: 16 16 C: 4 16 D: 16 4
以下程序的输出结果是:()ab = 4def myab(ab, xy): ab= pow(ab,xy) print(ab,end=" ")myab(ab,2)print( ab) A: 4 4 B: 16 16 C: 4 16 D: 16 4
以下程序的输出结果是: ab = 4def myab(ab, xy): ab= pow(ab,xy) print(ab,end=" ")myab(ab,2)print( ab) A: 16 4 B: 4 4 C: 16 16 D: 4 16
以下程序的输出结果是: ab = 4def myab(ab, xy): ab= pow(ab,xy) print(ab,end=" ")myab(ab,2)print( ab) A: 16 4 B: 4 4 C: 16 16 D: 4 16
已知x+y=4,xy=-12,求(1)x2+y2的值;(2)求(x-y)2的值.
已知x+y=4,xy=-12,求(1)x2+y2的值;(2)求(x-y)2的值.