下面程序段的执行结果为_______。 import numpy as np t = np.arange(120).reshape(3,4,5,2) t0=np.sum(t,axis=1) print(t0.shape)
下面程序段的执行结果为_______。 import numpy as np t = np.arange(120).reshape(3,4,5,2) t0=np.sum(t,axis=1) print(t0.shape)
已定义一个Shape抽象类,在此基础上派生出矩形Rectangle和圆形Circle类,二者都有GetPerim()函数计算对象的周长,并编写测试main()函数。class Shape{public:Shape(){}~Shape(){}virtual float GetPerim()=0;}
已定义一个Shape抽象类,在此基础上派生出矩形Rectangle和圆形Circle类,二者都有GetPerim()函数计算对象的周长,并编写测试main()函数。class Shape{public:Shape(){}~Shape(){}virtual float GetPerim()=0;}
What letter shape is Vietnam like A: L B: S C: T D: J
What letter shape is Vietnam like A: L B: S C: T D: J
因果系统的时域充分必要条件是( ) A: h(t)<0,t<0 B: h(t)=0,t<0 C: h(t)>0,t<0 D: h(t)=0,t>0
因果系统的时域充分必要条件是( ) A: h(t)<0,t<0 B: h(t)=0,t<0 C: h(t)>0,t<0 D: h(t)=0,t>0
动态显示Shape形状。提示:利用时间控件和随机函数实现,形状控件Shape属性的有效取值在[0, 5]区间。
动态显示Shape形状。提示:利用时间控件和随机函数实现,形状控件Shape属性的有效取值在[0, 5]区间。
In Figure (a), +t indicates the increase of the temperature and -t indicates the decrease of the temperature. The shape of bending moment diagram of is as shown in Figure (b).[img=603x369]1803b80c6f7f661.png[/img]
In Figure (a), +t indicates the increase of the temperature and -t indicates the decrease of the temperature. The shape of bending moment diagram of is as shown in Figure (b).[img=603x369]1803b80c6f7f661.png[/img]
But I just can’t ___________ how I can get into shape and fit into the dress in such a short time. Look at my body! I can’t help ____________.
But I just can’t ___________ how I can get into shape and fit into the dress in such a short time. Look at my body! I can’t help ____________.
形状(Shape)控件用于在容器对象中画预定义的几何图形,形状控件Shape属性用于设置其显示形状,默认值为0
形状(Shape)控件用于在容器对象中画预定义的几何图形,形状控件Shape属性用于设置其显示形状,默认值为0
若正弦波形与坐标原点重合则有()。 A: t=0;Φ>0 B: t=0;Φ=0 C: t=0;Φ<0 D: t=0;Φ=180°
若正弦波形与坐标原点重合则有()。 A: t=0;Φ>0 B: t=0;Φ=0 C: t=0;Φ<0 D: t=0;Φ=180°
对于理想气体,下述结论中正确的是:() A: 、(¶H/¶T)V=0 (¶H/¶V)T=0 B: 、(¶H/¶T)p=0(¶H/¶p)T=0 C: 、(¶H/¶T)p=0(¶H/¶V)T=0 D: 、(¶H/¶V)T=0 (¶H/¶p)T=0
对于理想气体,下述结论中正确的是:() A: 、(¶H/¶T)V=0 (¶H/¶V)T=0 B: 、(¶H/¶T)p=0(¶H/¶p)T=0 C: 、(¶H/¶T)p=0(¶H/¶V)T=0 D: 、(¶H/¶V)T=0 (¶H/¶p)T=0