（6-2）以下代码会出现编译错误。
class Base{
public Base () {
System.out.println("1");
}
public void Base () {
System.out.println("2");
}
}
class Base{
public Base () {
System.out.println("1");
}
public void Base () {
System.out.println("2");
}
}
举一反三
- 以下程序的编译和运行结果为？ abstract class Base{ abstract public void myfunc(); public void another(){ System.out.println("Another method"); } } public class Abs extends Base{ public static void main(String argv[]){ Abs a = new Abs(); a.amethod(); } public void myfunc(){ System.out.println("My Func"); } public void amethod(){ myfunc(); } }
- 选择下面程序运行的结果，并说明原因class Base{Base(){System.out.println("Base");}}public class Checket extends Base{Checket(){System.out.println("Checket");super();}public static void main(String[] arg){Checket c = new Checket();}}
- 如何能使程序调用Base类的构造方法输出"base constructor"; class Base{ Base(int i){ System.out.println("base constructor"); } Base(){ } } public class Sup extends Base{ public static void main(String argv[]){ Sup s= new Sup(); //One } Sup() { //Two } public void derived() { //Three } }
- 当你编译运行下列程序代码,会得到什么结果? 。 private class Base{ Base(){ int i = 100; System.out.println(i); } } public class Pri extends Base{ static int i = 200; public static void main(String argv[]){ Pri p = new Pri(); System.out.println(i); } }
- 中国大学MOOC: 下列代码中构造方法的返回类型是（）public class Village { Village () { System .out .println(“hiding in Village”) ; } public static void main( String args [ ]) { Village c =new Village ( ) ;}class Village { public static void main( String args [ ]) { Village c =new Village ( ) ; } Village () { System .out .println(“hiding in Village”) ; } }