举一反三
- The gap generated by hydrolysis of mismatch site in replication can be repaired by DNA polymerase I in E. coli. A: 正确 B: 错误
- Which of the following are NOT true about DNA polymerase I in E. coli: A: It can repair the gap in the single-strand DNA. B: It can replace DNA polymerase III to add dNTP into DNA chain when DNA template is damaged. C: Using dNTP as substrate. D: It possesses activity of 5’→3’ endonuclease.
- DNA polymerase III is the largest DNA polymerase in E. coli（）
- E coli DNA polymerase III: A: can initiate replication without a primer. B: is efficient at nick translation. C: is the principal DNA polymerase in chromosomal DNA replication. D: represents over 90% of the DNA polymerase activity in E: requires a free 5'-hydroxyl group as a primer.
- 1966 Scientist Kiwako Sakab and Reiji Okazaki discovered fragments, now known as Okazaki fragments, during their research on DNA replication of Escherichia coli. They continued their research studying bacteriophage DNA replication in Escherichia coli. Which enzyme is used during replication to attach Okazaki fragments to each other? A: DNA ligase B: DNA polymerase C: RNA polymerase D: reverse transcript
内容
- 0
Both DNA polymerase and RNA polymerase are needed in DNA replication process.()
- 1
The polymerase which is used in DNA replication is ( ) A: DNA-dependent RNA polymerase B: DNA-dependent DNA polymerase C: RNA-dependent RNA polymerase D: RNA-dependent DNA polymerase E: none of above
- 2
Both DNA polymerase and RNA polymerase are needed in DNA replication process. A: 正确 B: 错误
- 3
DNA replication requires: (1) DNA polymerase III, (2) helicase, (3) DNA polymerase I, (4) DNA-directed RNA polymerase, (5) DNA ligase, the correct order of their participation is: A: 2,3,4,1,5 B: 4,2,1,5,3 C: 4,2,1,3,5 D: 2,4,1,3,5
- 4
DNA<br/>replication requires: (1) DNA polymerase III, (2) helicase, (3) DNA<br/>polymerase I,<br/>(4) DNA-directed RNA polymerase, (5) DNA ligase, the correct order of<br/>their participation is:() A: 4,3,1,2,5 B: 2,3,4,1,5 C: 4,2,1,5,3 D: 4,2,1,3,5 E: 2,4,1,3,5