设[tex=0.643x1.0]Ft8KOBgb78fnKY0jEt4Rsg==[/tex]是数域[tex=13.714x1.357]7U057BYvehf1pYY/BkuDL7ZDOwvHY57hcSx+pip/OZBoZuRby7ZsRJ5Xdk0mCIZVhKPf11gqH0k2TM9O6dbIa4sNa9Ueda0coq+IDkoXuWE=[/tex],[tex=4.0x1.214]/XBovSn7AvnJ2pYJ76V1qKQD9ha4mrRfoZRtnnmY1Ts=[/tex]，并且秩[tex=8.0x1.214]n3I6I6tLSRsyp3SSeARZqD1pwIChdVNSnuKOe9wGAec=[/tex]，证明秩[tex=4.643x2.786]075gCzZzsMRb6HYXYk9X99H0yM0sbTWlaqoFfzUnW/OtZG4/M4r20gCtj3px0rmwfc8gq9A3bpfud7tFYG+R4g==[/tex]的充要条件是[tex=1.857x1.0]vXrgkuWNZRH6TLvjVRu6jg==[/tex]
举一反三
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 以下程序段实现的输出是（）。for(i=0;i<;=9;i++)s[i]=i;for(i=9;i>;=0;i--)printf("%2d",s[i]);[/i][/i] A: 9 7 5 3 1 B: 1 3 5 7 9 C: 9 8 7 6 5 4 3 2 1 0 D: 0 1 2 3 4 5 6 7 8 9
- 下面是图的拓扑排序的是？(多选)[img=340x240]1802faef6ebcc2a.png[/img] A: 2 8 0 7 1 3 5 6 4 9 10 11 12 B: 2 8 7 0 6 9 11 12 10 1 3 5 4 C: 8 2 7 3 0 6 1 5 4 9 10 11 12 D: 8 2 7 0 6 9 10 11 12 1 3 5 4