求两点P(1,0,1)和Q(2,3,5)连线的方程为( )。
A: x-1=y/3=(z-1)/4
B: x-2=(y-3)/4=(z-5)/3
A: x-1=y/3=(z-1)/4
B: x-2=(y-3)/4=(z-5)/3
举一反三
- 执行以下语句的结果:dict1={"x":1,"y":2,"z":3}dict2={"x":4,"a":5}dict1.update(dict2) A: {"x":1,"y":2,"z":3,"x":4,"a":5} B: {"x":4,"a":5,"x":1,"y":2,"z":3} C: 有重复项,结果有误! D: {"x":4,"y":2,"z":3,"a":5}
- int x=3,y,z;<br/>y=-x++;<br/>z=y+8/++x;<br/>Console.WriteLine{{0},{1},{2}",x,y,z);<br/>此程序的输出结果是____。 A: 5,-3,-2 B: 4,-3,-1 C: 4,-4,-2 D: 5,-4,-2
- 若x=[1 2 3 4 5];y=[2 -1 4 3 -2];则z=x.*y=()
- 已知直线的一般方程\( \left\{ {\matrix{ {x - 2y - z + 4 = 0} \cr {5x + y - 2z + 8 = 0} \cr } } \right. \), 则其点向式方程为( ) A: \( { { x - 2} \over 2} = {y \over { - 3}} = { { z - 4} \over {11}} \) B: \( {x \over 5} = {y \over { - 3}} = { { z - 4} \over {11}} \) C: \( { { x - 2} \over 5} = { { y + 1} \over { - 3}} = { { z - 4} \over {11}} \) D: \( { { x - 2} \over 2} = { { y + 1} \over { - 3}} = { { z - 4} \over {11}} \)
- intx=5,y=8,z=7;表达式z=!(x>y)||(x=1,y=3)计算后的结果 A: x=1,y=3,z=1 B: x=1,y=3,z=0 C: x=5,y=8,z=0 D: x=5,y=8,z=1