半径为[img=14x19]1802ce0c22890ef.png[/img]的半球形水池装满水(水的密度为1),现将水全部吸完,需要做功 = ( )
A: [img=159x52]1802ce0c2cf2495.png[/img]
B: [img=139x52]1802ce0c38f69f1.png[/img]
C: [img=92x52]1802ce0c41472eb.png[/img]
D: [img=92x52]1802ce0c4a1f149.png[/img]
A: [img=159x52]1802ce0c2cf2495.png[/img]
B: [img=139x52]1802ce0c38f69f1.png[/img]
C: [img=92x52]1802ce0c41472eb.png[/img]
D: [img=92x52]1802ce0c4a1f149.png[/img]
举一反三
- 半径为[img=14x19]1802f66212d35d7.png[/img]的半球形水池装满水(水的密度为1),现将水全部吸完,需要做功 = ( ) A: [img=159x52]1802f6621e22dbc.png[/img] B: [img=139x52]1802f66227cf8a7.png[/img] C: [img=92x52]1802f662309f98d.png[/img] D: [img=92x52]1802f6623928022.png[/img]
- 半径为[img=14x19]1802e54805206e6.png[/img]的半球形水池装满水,现将水全部吸完,需要做功 = ( ) A: [img=159x52]1802e54810708bd.png[/img] B: [img=139x52]1802e5481ac4c8b.png[/img] C: [img=92x52]1802e548233aa37.png[/img] D: [img=92x52]1802e5482b64510.png[/img]
- 半径为[img=14x19]1802ce0971c7b95.png[/img]的半球形水池装满水,现将水全部吸完,需要做功 = ( ) A: [img=159x52]1802ce097b230cc.png[/img] B: [img=139x52]1802ce0986594ef.png[/img] C: [img=92x52]1802ce098f9b490.png[/img] D: [img=92x52]1802ce099831a26.png[/img]
- 函数[img=73x26]1803467b5e85eef.png[/img]的极值为( ). A: f(0)=1 B: f(1)=2 C: x=0 D: x=1
- 函数f(x)=[img=40x76]17e0bf8d391c13e.png[/img]的不连续点为( ) 未知类型:{'options': ['x=0', ' x=[img=43x39]17e0bf8d4513730.png[/img](k=0,±1,±2,…)', ' x=0和x=2kπ(k=0,±1,±2,…)', ' x=0和x=[img=43x39]17e0bf8d4513730.png[/img](k=0,±1,±2,…)'], 'type': 102}