举一反三
- print([i for i in range(5)]) A: [0,1,2,3,4,5] B: [0,1,2,3,4] C: [1,2,3,4,5] D: i
- for i in range(4): if i%2==0: print(i) break print(i) 结果是
- 已知 vec=[[1,2],[3,4]],则表达式［［row[i] for row in vec] for i in range(len(vec[0]))]的值为（ )[/i]
- 下面代码的输出结果是： 。ls = [[1,3,6],[4,6,3],[2,8,5]]sum1,sum2 = 0,0for i in range(3):sum1 = sum1 + ls[i][i]sum2 = sum2 + ls[i][2-i]print("sum1={},sum2={}".format(sum1,sum2))[/i][/i][/i]
- 已知列表lst=[1,2,3]，则分别执行以下代码，结果为[1,4,9]的是： A: for i in lst: i=i**2print(lst) B: for i in range(0,3): lst[i]**=2print(lst) C: for i in range(0,3): lst[i]=i**2print(lst) D: for i in range(0,3): lst[i]+=lst[i]print(lst)
内容
- 0
已知列表m=[[1,2],[3,4]]，有列表a=[[row[i] for row in m] for i in range(2)]，则a[0][1]是[/i]
- 1
下面代码的输出结果是（ ）。 a=[[1,2,3],[4,5,6],[7,8,9]] s=0 for i in range(2): for j in range(3): s+=a[i][j] print(s)[/i] A: 15 B: 6 C: 45 D: 21
- 2
编写一段代码使用for循环输出1~10之内的奇数,以下哪些选项的结果是正确的?( ) A: for i in range(10): if i % 2 == 1: print(i) B: for i in range(9): if i % 2 == 0: print(i) C: for i in range(11): if i % 2 == 1: print(i) D: for i in range(12): if i % 2 = 0: print(i)
- 3
阅读以下程序，输出结果是： w=[] for i in range(1,20): if (i%5==0) and (i%7!=0): w.append(str(i)) print (w)
- 4
已知 vec = [[1,2], [3,4]],则表达式 [[row[i] for row in vec] for i in range(len(vec[0]))]的值为______________()_________。[/i] A: [1, 2, 3, 4] B: [[1, 2, 3], 4] C: [[1, 3], [2, 4]] D: [1, 2, [3, 4]]