• 2022-06-11
    己知滤波器的差分方程为[tex=11.714x1.357]9Z5wOgfwiuyNWtDiWXLLcOUA+FnJqoAmKkftvvjtErM=[/tex]如果差分方程改为[tex=11.071x1.357]9GhmSm0Iu9TPIfmtdJPdJigvQ4qN4BjrIy4ObDKw9k4=[/tex]
  • [tex=11.071x3.929]9GhmSm0Iu9TPIfmtdJPdJrQgPBUjyZgDB53F7/GRrL3tHyTkQadrnlkGsyeGaT+nmQY8ybliyB4C3hsoo1+f5A==[/tex]极点为[tex=3.786x1.286]cLU6D/PnU9kk3FRpW7Dg5Q==[/tex],可以判晰这是一个高通滤波器。由滤波器的零极点分布判断幅度特性的最大值在[tex=2.571x0.786]75ok92y3BTDxPxRX1a57Jg==[/tex]处,因此[tex=27.571x6.857]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[/tex]

    内容

    • 0

      假设x=4,y=2,m=5,n=4,w=12,t=9,则经过表达式(w=x 0  9

    • 1

      求下列函数的一阶差分和二阶差分:(4)[tex=5.0x1.5]FAG7Q9j7ht0zmIWYDZpiDw==[/tex]

    • 2

      己知系统的差分方程求系数向量[tex=22.786x1.357]jr+ZBvupYf1/awO4hILfQSB/GaRq7y3+XXuvXp/YZDYs6VhyZ/hmIOnPjsSjEUj4[/tex]

    • 3

      方程2(x-3)+5=9的解是(). A: x=4 B: x=5 C: x=6 D: x=7

    • 4

      3.设函数$f(x)={{x}^{4}}\sin x$,则${{f}^{(9)}}(0)=$( )。 A: $\frac{9!}{5!}$ B: $\frac{5!}{9!}$ C: $\frac{1}{5!}$ D: $0$