• 2022-06-15
    函数y=2cos(2x-π/3)+1在区间[-π/4,π/4]上的值域是
  • -pai/4<=x<=pai/4-pai/2<=2x<=pai/2-5pai/6<=2x-pai/3<=pai/6-3^1/2/2<=cos(2x-pai/3)<=11-3^1/2<=y<=3

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    • 0

      ‏ y = &#91;1, 2, 3, 4&#93;,y=y+&#91;8&#93; ,则y的取值不正确的是‏ A: [1, 2, 3, 4, 8] B: [8,1, 2, 3, 4,] C: [1, 2, 3, 8, 4] D: [1, 2, 8, 4,3]

    • 1

      已知 vec = &#91;&#91;1,2&#93;, &#91;3,4&#93;&#93;,则表达式 &#91;&#91;row[i] for row in vec&#93; for i in range(len(vec&#91;0&#93;))&#93;的值为______________()_________。[/i] A: [1, 2, 3, 4] B: [[1, 2, 3], 4] C: [[1, 3], [2, 4]] D: [1, 2, [3, 4]]

    • 2

      若函数f(x)的定义域为&#91;0,1&#93;,值域为&#91;1,2&#93;,则函数f(x+2)的定义域,值域分别为(  )A.&#91;0,1&#93;,&#91;1,2&#93;B.&#91;2,3&#93;,&#91;3,4&#93;C.&#91;-2,-1&#93;,&#91;1,2&#93;D.&#91;-2,-1&#93;,&#91;3,4&#93;

    • 3

      设X在区间&#91;2,4&#93;上服从均匀分布,则P(1<X<3)=________. A: 1 B: 1/3 C: 1/2 D: 2/3

    • 4

      求y=-3sin(2x-π/3)x∈&#91;-π,π&#93;的单调递增区间