设函数f(x)有二姐连续导数,且(x->0)lim[f(x)-a]/[e^x^2-1]=0,(x->0)lim[f‘’(x)+1]/[1-cosx]=2,则
举一反三
- lim(x->0)[1-x^2-e^(-x^2)]/[x(sinx)^3]
- 设函数f(x)在(-∞,+∞)内满足f(x)=f(x-π)+sinx且f(x)=x(x∈[0,π])则
- 设f(x)是多项式,且lim(x→∞)[f(x)-x^3]/x^2=2,且lim(x→0)f(x)/x=1,求f(x)
- 已知f(x)在x=x0处的导数为4,lim[x→x0][f(x)-f(x0)]/2(x0-x)]=_______
- 设总体X的概率密度为:f(x,θ)=e的[-(x-θ)]次方,x≥θ;0,x