• 2022-06-15
    设函数[tex=8.429x2.786]Pgq88fyWbmR8hJT1DoNxPB30WByqnerT4pr3KKWvmumwI5N/zL3V3VLFT2YsbDFKQN7XyaA1M2VBedvsXO7QRfaVtpdP+9npimZLJjy7sws=[/tex], 求导数 [tex=2.0x1.429]ASsUZ0gYTpcKboibdc9u3A==[/tex]