设X是取自总体 N(μ,σ2)的一个样本,μ 的无偏估计量是( )
A: 1/4·X1+2/4·X2
B: 2/4·X1+1/4·X2+1/4·X3
C: 1/4·X1+1/4·X2+1/4·X3
D: 2/4·X1+2/4·X2+1/4·X3
A: 1/4·X1+2/4·X2
B: 2/4·X1+1/4·X2+1/4·X3
C: 1/4·X1+1/4·X2+1/4·X3
D: 2/4·X1+2/4·X2+1/4·X3
举一反三
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- 阅读下面程序,则disp语句所显示结果为()。x=1;while x~=5disp(x)x=x+1;end A: 1 3 2 4 B: 1 2 3 4 C: 2 3 4 5 D: 1 3 4 2
- 设矩阵,已知A的特征值是λ1=2,λ2=λ3=1,则()。 A: x=-4,y=3 B: x=-4,y=-3 C: x=4,y=-3 D: x=4,y=3