(1)[tex=5.857x1.5]ONt5znqkvvBN5WWzDw505yf1NA8Kd1ZEm6O2Nx967Mg=[/tex] 则[tex=4.214x1.357]R4j4uI0Ptc9bwK2Et9hm4w==[/tex] ,[tex=5.214x1.357]4a6nfH2/cKH+GCNkNUVTYQ==[/tex] .(2) 设 [tex=8.0x1.357]IVKm5JF13gC4KKoo1XzulUVTQh1uJ6CF8EHaVwPyEn4=[/tex]为互异节点 [tex=2.357x1.357]mvLWkWF8OwJMmgxLkrJOSg==[/tex] 为对应的 [tex=0.5x1.0]swhA5SpCD6lPteGlwRbm9g==[/tex] 次[tex=4.214x1.214]9zbCebhtKGz4jfjRUxdgxA==[/tex]插值基函数,则[tex=5.214x3.429]0CCJvvl9r5u499VydE0OaR1FmIlDFk2sEEfMzOGgJpmn+iWC7nfhv+CiJhORKFQO[/tex] ,[tex=6.5x3.429]0nlNyI9u3B/Jv73WeDZ6Lfe80P2e2IX8hqlPOSZ3ySc01aS9jDvxUWgDoT0ifyJXPZej1xADlMNQ73kshJ8fSw==[/tex][tex=6.0x1.571]gwHI6QHOsiB3OdDDmf05E0+gbGHh/eCadqh+YqQPiuhlDuNAW5lj0t/voNNt7Yqv[/tex] .(3) [tex=9.071x2.357]+oynhsGqDwsjmIkOHmSOLVKx4B9iKU/KInD25t3icMsZ/yimz3z8zB/9I4IRfE6P[/tex]其中 [tex=5.857x1.214]9DXH2uuxn6jefBQNsANSeS2QaS/HN2ERRLaGPwN4Me4=[/tex] 则 [tex=2.857x1.429]gH2bC/VfSfxhWCxMTAYGinkdEpkdIi3iN1fEYX17kDk=[/tex] ,[tex=2.857x1.429]zulaiHU0dpBMUsMdCFuJTrNuk7rsxj5M988FMXeUdr8=[/tex] .(4) [tex=18.786x3.357]Ri4nmezVlzGkSBSYaBgygO5AmbH4+9ANzwJc+ZWARJ/z6fzyL2esd66TpBXtSg1u/smuZaE0CLgtNZAH60ZA5MbvkDO98Ha9yP/i2GjxYrOVvEU26OXp3qMGD38WDBZs3EI+wOKmGHfRls7Tn52H16I+nXMo/Fmehzwwlp7SOu9PH5ew4EAbBv0M1uJXkyHh[/tex] 是以 [tex=0.786x1.214]U0nuSVAug2JTcIr7mYBF9g==[/tex][tex=1.5x1.214]DeuxSwY77MuKEtQTCwEdNQ==[/tex]为节点的三次样条函数,则 [tex=1.214x1.0]NQwg71UJhse/Y3t96V3t8Q==[/tex] ，[tex=1.214x0.786]NWhjIVL1/mDVdDWwcjkrEA==[/tex] .(5) 满足条件[tex=13.571x1.429]f0WRCwvmjNaxN9/lKtSD6G5WucnDykMQuLcJmWE1cMLqd095ncA3hoB5/6F1xzAE[/tex]的插值多项式[tex=2.786x1.357]TqKy43ahIi5B2/CwSmax2w==[/tex] .
举一反三
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 输出九九乘法表。 1 2 3 4 5 6 7 8 9 --------------------------------------------------------------------- 1*1=1 2*1=2 2*2=4 3*1=3 3*2=6 3*3=9 4*1=4 4*2=8 4*3=12 4*4=16 5*1=5 5*2=10 5*3=15 5*4=20 5*5=25 6*1=6 6*2=12 6*3=18 6*4=24 6*5=30 6*6=36 7*1=7 7*2=14 7*3=21 7*4=28 7*5=35 7*6=42 7*7=49 8*1=8 8*2=16 8*3=24 8*4=32 8*5=40 8*6=48 8*7=56 8*8=64 9*1=9 9*2=18 9*3=27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=81
- 下面说法错误的是（ ）。知识点：列表推导式 A: dict([(x, x**2) for x in range(6)]) 创建的字典是{0: 0, 1: 1, 2: 4, 3: 9, 4: 16, 5: 25} B: [[x*3+y for y in range(1,4)] for x in range(3)] 创建的是二维列表 [[1, 2, 3], [4, 5, 6], [7, 8, 9]] C: number = [-2, 4, 6, -5]string = 'ab'z = [(i, j) if i>0 else (-i, j) for i in number for j in string]这段代码创建的列表为[(2, 'a'), (2, 'b'), (4, 'a'), (4, 'b'), (6, 'a'), (6, 'b'), (5, 'a'), (5, 'b')] D: ' '.join([i for i in range(1,11)])的运算结果为字符串'1 2 3 4 5 6 7 8 9 10'