[tex=5.786x2.643]QzGp9F7MUycneJXlxr7LGv0WEuQCML3apLSU50zfACJ86iyT7kwNo9+E5XLyPCBp[/tex].
举一反三
- set1 = {x for x in range(10) if x%2!=0} set1.remove(1) print(set1) 以上代码的运行结果为？ A: {1, 3, 5, 7, 9} B: {1, 3, 5, 7} C: {3, 5, 7, 9} D: {3, 5, 7}
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- [tex=5.786x2.643]QzGp9F7MUycneJXlxr7LGv0WEuQCML3apLSU50zfACJ86iyT7kwNo9+E5XLyPCBp[/tex].
- 【单选题】请用地点定桩法在4分钟内记忆数字。 4 0 1 3 6 3 5 1 9 8 8 9 7 2 9 3 0 9 5 3 1 7 7 5 2 3 3 0 5 0 1 4 1 3 8 3 5 7 9 7 (5.0分) A. 已背 B. 未背
- 已知列表x=[3, 5, 6, 7, 9]，那么x[::-1]的结果是 A: [3, 9] B: [3, 5, 6, 7, 9] C: [3, 5, 6, 7] D: [9, 7, 6, 5, 3]