τ(2020) = ,σ(2020)=
举一反三
- 下面代码的执行结果是( ) 。ls = ["2020", "20.20", "Python"] ls.append(2020)ls.append([2020, "2020"])print(ls) A: ['2020', '20.20', 'Python', 2020, 2020, '2020'] B: ['2020', '20.20', 'Python', 2020, [2020, '2020']] C: ['2020', '20.20', 'Python', 2020] D: ['2020', '20.20', 'Python', 2020, ['2020']]
- 下面代码的执行结果是: ls = ["2020", "20.20", "Python"] ls.append(2020) ls.append([2020, "2020"]) print(ls) A: ['2020', '20.20', 'Python', 2020, ['2020']] B: ['2020', '20.20', 'Python', 2020, 2020, '2020'] C: ['2020', '20.20', 'Python', 2020] D: ['2020', '20.20', 'Python', 2020, [2020, '2020']]
- 以下代码的输出结果是______。ls = ["2020", "20.20", "Python"]ls.append(2020)ls.append([2020, "2020"])print(ls) A: ['2020', '20.20', 'Python', 2020] B: ['2020', '20.20', 'Python', 2020, [2020, '2020']] C: ['2020', '20.20', 'Python', 2020, 2020, '2020'] D: ['2020', '20.20', 'Python', 2020, ['2020']]
- 下面代码的执行结果是:( )ls= [“2020”, “20.20”, “Python”]ls.append(2020)ls.append([2020, “2020”])print(ls) A: [‘2020’, ‘20.20’, ‘Python’, 2020] B: [‘2020’, ‘20.20’, ‘Python’, 2020, [2020, ‘2020’]] C: [‘2020’, ‘20.20’, ‘Python’, 2020, [‘2020’]] D: [‘2020’, ‘20.20’, ‘Python’, 2020, 2020, ‘2020’]r
- 以下代码的输出结果是( )。 ls = ["2020", "20.20", "Python"] ls.append([2020, "2020"]) [br][/br]print(ls) A: ['2020', '20.20', 'Python', [2020, '2020']] B: ['2020', '20.20', 'Python', 2020, ['2020']] C: ['2020', '20.20', 'Python', 2020,] D: ['2020', '20.20', 'Python', 2020, '2020']