证明一个 [tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex] 一循环置换的阶是 [tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex].
举一反三
- 计算下列矩阵的 [tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex] 次幂, 其中 [tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex] 为正整数:[tex=7.929x4.786]SG13E7iu2HdaLVWfWJMdasNcssnOsnpcSXP9pfv8ZVudX8uBxPyIW+BW1iuKqBWPQy19xF0hvC5K+ZJXm49WVAb1VZdwsjQNiE6Ohf5lij4=[/tex]
- 计算下列矩阵的 [tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex] 次幂, 其中 [tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex] 为正整数:[tex=8.286x3.5]QN0fTQbn6M33pU3gx/S2ssRzVqpWUEMlPB1F8em9pxPHPIIzaitaqaXj3OkAP2YhwLgtNTq7mVpRVmzCUDjgMxeK0fRBchQXdLQiPBE6zvU4+B34aF8ZRVS24QkM3V+Y[/tex]
- 从 [tex=2.286x1.0]Tv9J6hl5OfwCno6jJv7xtw==[/tex] 的整数中取一个数，若取到整数 [tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex] 的概率与 [tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex] 成正比，求取到偶数的概率.
- 当[tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex]为何值时，反常积分[tex=5.857x3.429]PJkWCDHq0HBl1uIZQZIQaCJeYEBINEa3r1jVRLOCV3RAYxRTzznIBmThvoc5BKDWEufXbmYTxx3twNmSd5TmhQ==[/tex]收敛? 当[tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex]为何值时，这反常积分发散?当[tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex]为何值时，这反常积分取得最小值?
- 设 [tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex] 为正整数，证明:[tex=7.286x2.714]WdYFOXfG5nnGW/WgiEfXS7KSJGNH9TOu8OctQH+TBUAmN+2wRfhYp9VdsOm9mviu[/tex].