• 2022-05-26
    阅读下段代码 import java.io.*; public class Example{ public static void main(String[] args) throws Exception { FileInputStream fis = new FileInputStream("file.txt"); FileOutputStream fos = new FileOutputStream("copy_file.txt"); int ch = 0; while((ch =fis.read())!=-1){ fos.write(ch); } fos._______; fis.close(); } } 请说出下划线上,填写的方法名称
  • write()

    举一反三

    内容

    • 0

      阅读下列代码 import java.io.*; public class Example{ public static void main(String[] args) throws Exception { // 创建一个带缓冲区的输入流 BufferedInputStream bis = new BufferedInputStream(new ________( "src.txt")); // 创建一个带缓冲区的输出流 BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream("des.txt")); int len; while ((len = bis.read()) != -1) { bos.write(len); } bis.close(); bos.close(); } } 请说出程序中,下划线位置的答案( )

    • 1

      下列哪个选项定义了带有缓存的文件字节输入流 A: BufferedInputStream bis = new BufferedInputStream(new FileInputStream(...)); B: BufferedOutputStream bos = new BufferedOutputStream(new FileInputStream(...)); C: FileInputStream fis = new FileInputStream(new BufferedInputStream(...)); D: FileOutputStream fis = new FileOutputStream(new BufferedOutputStream(...));

    • 2

      如果在一台 PC 机的c:\source目录运行如下代码: import java.io.*; class Path { public static void main(String[] args) throws Exception { File file = new File('Ran.test'); System.out.println(file.getAbsolutePath()); } } 则,期望的输出结果为?

    • 3

      有如下代码: public class Test{ public static void main(String args[]) { String str = new String("World"); char ch[] = {'H','e','l','l','o'}; change(str,ch); System.out.println(str + "and" + ch); } public static void change(String str, char ch[]) { str = "Changed"; ch[0] = 'C'; } } 运行后输出的结果是:

    • 4

      下列程序的功能是显示用户在命令行方式下指定的任意驱动器目录,请补充程序。 import java.iO.*; public class FindDirectories { public static void main (String args[ ]) { if(args.length= =0) args=new String[ ]".."}; try { File pathName=new File(args [0]); String[]fileName=pathName.list( ); for(int i=0;<fileName.length;i+ += { File f=new 【 】 if(f.isDirectory( )) { System.out.println(f.getCanonicalPath( )); main(new String[ ] { f.getPath( ) }); } } = catch(IOException e) { e.printStackTrace( ); } = =