• 2022-05-27
    测定试样中[tex=2.143x1.214]rL2D81vVImqfCVTVfLJFOQ==[/tex]质量分数[tex=1.929x1.357]oQ17HjhAwZez67DjgHU/VQ==[/tex]数据如下: [tex=13.214x1.214]iRUbsNf7034vbQ9cV3zkaTOj0M4/C64Bndp7vEcg2BNaKGfZCWiMaH/QHeFXY2pZ[/tex] 用[tex=3.143x1.0]Snzeh/Xiawic+RPoxXC6hQ==[/tex]法及 [tex=0.857x1.214]to/MrMoO1ux8UhZHnpEvBg==[/tex] 检验法对可疑数据决定取舍,求平均值、平均偏差[tex=0.714x1.143]Wrol/JlruthDg1+LVGB/Ig==[/tex] 、标准偏差 [tex=0.5x0.786]BgHR5DBWke5rTEC5XEckiQ==[/tex]和置信度选[tex=1.857x1.143]aeUqgNaXXrekvJO4iTqloA==[/tex]及 [tex=1.857x1.143]tnsbeZpQzrh/W5C2M9k/gg==[/tex] 的平均值的置信范围。
  • 解: 将测定值由小到大排列[tex=13.214x1.214]yPmvlrYuI5G8xlhkka+yY19cMcZ0Tlk4HCRq9ZUcntyKFarljNI+b1jUOlXTKfYF[/tex] 可疑值为 [tex=1.0x1.0]YLAI7ItDst7/NdWQP//4+w==[/tex][tex=1.286x1.357]VAHhaW1te0xvoqDVN54/dg==[/tex]用 [tex=3.143x1.0]Snzeh/Xiawic+RPoxXC6hQ==[/tex] 法决定取舍 [tex=2.786x1.0]LT+q/nG/M6Gwzh7RPG1yag==[/tex]为可疑值由原始数据求得[tex=8.857x1.143]647yf5+HsmCJX5nWGEE3FG/UMHBEzzbmmc9I8+HGolUtX/FQ0866BGIcndAgpVYf[/tex][tex=16.286x2.0]/eN4CV6KBYjrK93dLglXnqFI14/KxgU9XbHk/JRdnX10HUo1wu0HKjloYLsJJkkq5B8yIbyJHvKtAakbLoP/KJN5yBmJEWimmj6ZztUTWYs=[/tex]查表[tex=1.786x1.143]gjPWe3Adfd9XhgVFvePYIg==[/tex], 置信度选[tex=4.214x1.286]SCHHtCgH/08QrJ1AvX3Cqg==[/tex]时, [tex=4.786x1.5]0S/xm6sNZdLRoi4etiTfIPfDzMp3Vhg0244NifDHLKg=[/tex][tex=5.857x1.5]MEza6U5vCpa1k/EpRPvs54uTLVaMvkyHVY1bBJMZiHg=[/tex] 表, 故[tex=2.643x1.143]lBNkDe6coYMU59BLCprdvw==[/tex]应予保留。[tex=1.286x1.357]BEB68bP4vOVk/XYYizw11w==[/tex] 用[tex=0.857x1.214]to/MrMoO1ux8UhZHnpEvBg==[/tex] 值检验法[tex=17.786x2.143]+nkHqedCakN1BhuxpoYZO2Z6nJ/VJZgP7Go5ir5cgOHUPXWm8HPiuwdPMmePddpC6gsWJ/V4J8MpgxSov4Rx3f08jalaU49KVpurFpt3TRD7O/8A3F+ysRGki5RiOBfF[/tex]查表[tex=4.143x1.214]IXDnFfv6zbImNggIacFvzw==[/tex]时, [tex=4.643x1.214]et7RcyISP2VqMH73mxTJoxhakOoULENDYCVZEaplR4g=[/tex]   [tex=5.857x1.5]sHcMUnzKqafv1ShdJ9ftsGzSzVEEnreTdBlfTS4B6Z9TR+muFWvOdX2tKMAuUH+P[/tex]故 [tex=2.643x1.143]lBNkDe6coYMU59BLCprdvw==[/tex]应予保留。两种判断方法所得结论一致。[tex=23.857x2.786]SY4lqjTObW+qKj8aYR3J/mFipSwLkm0ook3JQGq/uOeqXBHd/lglAqamGntoIKNZWmM1fhrioPbiXRD9LfxvzV6thc5QVvztw3Is22RhOqE=[/tex][tex=22.286x2.786]+Xhr17PomYqg8lHQBMLOjqTyJJjmPLJjqOMJ6W/CHOEyxOdQmvydA5ZAP394vhpj2vdyISQb9gfTHwTDFYEn/oVNaWUugUzItpNlY98BjBI=[/tex][tex=28.357x2.786]yuNxKTm5Hz+LXdq46kLgZJzXNpCFT7jL9ph1Y3Nppk4L4btia6PxtD+/prFl3Ck/o9Owwo8o4iHDh5kILD5rPXUZcVZU/1igtK6JQ5SYsal7Hhb/DHj/1+JDNzUL+EPYyh3e7iso6lvEjoJ9Q8DGKA==[/tex][tex=1.286x1.357]dF+j2ufB5JBOJwdIPfmkfg==[/tex]查表[tex=2.071x1.214]YEATPH+wHW0mTpv4lZfOBw==[/tex] 置信度为[tex=4.214x1.286]3X8YN55vSfRWHFWwGRwAEA==[/tex]时, [tex=3.429x1.0]+2804N44tilWR9XPFoETwg==[/tex]因此 [tex=18.429x2.786]JzsmhiNAi3IOgPiEqgcperWKUh+BRWv7ZGAXfpM27UTMv69Bc0e3ZIcPvSvvLsmc9hUbpXgVZp7r5ZbeP+D4Np/42fGEnN2VA1WlSuu6HSZFUT/b3Y1MHOtm/0BG/997[/tex]同理, 对于置信度为 [tex=2.143x1.286]HERQfL+HvnTbbtJ8mhgI9A==[/tex]可得[tex=19.286x2.786]JzsmhiNAi3IOgPiEqgcpeizRJRrdYqb4GLilBEyBmRNrIcfjUJzNhMAN+NNJxiZlLJ32uDARqFEGM+M5kiVIdy5Ze4ZDcQnyjxIcaM/6jlqA/zv/a/DGUM04okCFhpSA[/tex]

    内容

    • 0

      用[tex=0.786x1.214]qWTwUSIEBK1EwCOmwQzggg==[/tex]检验法,判断下列数据中,有无取舍[tex=0.5x1.0]LejCcgTCRXIa4uGYudUsSQ==[/tex] 置信度为[tex=1.857x1.143]aeUqgNaXXrekvJO4iTqloA==[/tex]。[tex=11.0x1.214]y36a/kfqbFkiBU7YUoPpo9uE4GXyPZH+g4wQcKNkbqw=[/tex]

    • 1

      对于以下两种情形:(1)x为自变量,(2)x为中间变量,求函数[tex=2.214x1.214]sy9gaFRMGlrH59gm9bWSDg==[/tex]的[tex=1.5x1.429]5W5tOYbJ+LlsRP2dMsi4byxwtjvvL/3u7NEzPV5PWp0=[/tex]

    • 2

      用[tex=0.786x1.214]qWTwUSIEBK1EwCOmwQzggg==[/tex]检验法,判断下列数据中,有无取舍[tex=0.5x1.0]LejCcgTCRXIa4uGYudUsSQ==[/tex] 置信度为[tex=1.857x1.143]aeUqgNaXXrekvJO4iTqloA==[/tex]。[br][/br][tex=10.786x1.214]YlXHww4A+kqovJKmzzzy9QNxfw5NDWt7vF44o7c+RcU=[/tex]

    • 3

      求下列函数的导函数:(1) [tex=5.0x2.357]X/CieCDGJ7iPQ3YFWuscHxHrcIE/dPFa9tFyiJXze8A=[/tex](2)[tex=6.643x1.714]Oj74y/L+OxY81QME5JWMcl+7PZ2FGQswwvjgVhjq1Dmb6dBU0oAjZBW7eFBVjqo6[/tex]

    • 4

      设[tex=5.929x1.071]gAFI4ZzNAmjFfJAphmTsRQ==[/tex],若[tex=7.786x1.357]09fTpcwFMVcu1qrv9hyVbjaVP6Nu0Q7b0o9JCaEhfzk=[/tex],[tex=7.786x1.357]17Fg+KbtgLZdNaerla1J+g==[/tex],[tex=7.714x1.357]GzWWzGNDry0+/hdju2Gv5Q==[/tex],那么[tex=0.571x0.786]/uIIzJZ/1DPgc5sOsRpAXQ==[/tex],[tex=0.571x1.0]Tr41q2//n6lfFMLRmh8s0w==[/tex],[tex=0.5x0.786]rGd4FFr4Zsu+cuz6gxITMA==[/tex]的大小关系为 A: x<y<Z B: y<z<x C: z<x<y D: z<y<x E: 不能确定