• 2022-07-25
    计算以[tex=1.857x1.214]RMcRfwdf40cxgoROOl2A4A==[/tex]面上的圆周[tex=4.571x1.429]lm8OILLOFyZ37ALtaFSTDIPz6fRFXxhVCB6Zwd7l0X0=[/tex]围成的闭区域为底,er以曲面 [tex=4.357x1.429]eXG42LBlVmCe9OBZMR2NwQ==[/tex]为顶的曲顶柱体的体积.
  • 如图,即求[tex=8.429x3.357]iX5O37LbS5Zfq0MuGo2QbfiA1NoQCXKJhXzrGWCGrL/Ur42POUe1GcPue6PiwQU5ZQjHnFH/JMqR/Fy1cuLlIg==[/tex]其中[tex=10.643x1.571]JG2W9SJ7hhmceZReER8Zx14pJ/AfvTAfQP/foVtUZ/DieqHWdVH4Bfv4FC7EtcF1/alyD6XMTgeBeCpIAAlACg==[/tex]因为积分区域关于[tex=0.571x0.786]ZKO2xs0EgSemzoH7MSmYTA==[/tex]轴对称,且被积函数是关于[tex=0.5x1.0]yBR4oiFoTexGaFalQ7m8kg==[/tex]的偶函数,所以[tex=19.143x5.286]FEa5YoIOri+zD8IZRftd943yrKhuPTqoSg50Ce05pYGk9535QKkX5MYd79TPdrZl2/zEnyq/+JQi6Q+GCP5GpUS/1gi47pGaj+PRz4AeuJSg/1eF7Qjx8B8Qk0bUjZaoXro9ihxFPoWHWDVRIbPUVxlLxteZa5tXXmqjsfk4YVE17p0TmeE9hyFy+8jZtyyDzBi8UQ34J3k/HTLRyoivsqKa2xJ6mUOuS9RDWCI83NpmhemIqfO9WN85nIxpydTsHFZrbYDC0NinzwNJPNom3SD++oV/tf0eNzNhfMLp1uWpsyK/IP2w1+/78M2G9Xy7YdGpiLhq7MnqAtFG+c6cuzntxWY8BwK1uclQx36q882Le5URAaj9VXPe5YTna8teJ4+Lk8QoAokDLU3uXGm7Yg==[/tex]

    内容

    • 0

      求曲面[tex=4.357x1.429]eXG42LBlVmCe9OBZMR2NwQ==[/tex]与[tex=5.214x1.429]oOlyMWVDapTIIODTLRmv4z7vABwKZQWiRRGZ85MYpaQ=[/tex]所围成的立体在三个坐标面上的投影.

    • 1

      以\( xOy \) 面上的圆周\( {x^2} + {y^2} = ax \) 所围区域为底,曲面\( z = {x^2} + {y^2} \) 为顶的曲顶柱体的体积为( ) A: \( {3 \over {32}}\pi {a^4} \) B: \( {5 \over {32}}\pi {a^4} \) C: \( {7 \over {32}}\pi {a^4} \) D: \( {9 \over {32}}\pi {a^4} \)

    • 2

      一母线平行于 [tex=0.5x0.786]C7x+w8+jOPZzxFrGGne6Dw==[/tex]轴的柱体,它与[tex=1.857x1.214]8v+QaGH4dkCVbzRhgAvkuw==[/tex] 平面的交线是一封闭曲线.此封闭曲线所围区域为 [tex=1.357x1.357]4IH/MMxhnSVueDW7gOfozQ==[/tex],柱体的顶和底分别是曲面[tex=4.429x1.357]Jh2A9bwWj/MmFoTvJwQooA==[/tex]和[tex=4.429x1.357]yPW1JAuwvuWR4B8M0/ThVg==[/tex] .试用二重积分表示该柱体的体积.

    • 3

      利用柱面坐标计算下列积分:[tex=7.714x3.357]lqxpp1Okm+2z/2drYPfTVLzwBpkFGo2mDWuL/Ga4jlt1Dvd3IUx8h8C5JqDlsQfuEdV6prhGAtegNiMkvBJHzdkDbKsHi2vE8ToiS6YCs1s=[/tex] 是由曲面 [tex=3.929x1.429]eXG42LBlVmCe9OBZMR2NwQ==[/tex]与 [tex=2.286x1.214]gBzqtDgEWxDF0TX+5reb9w==[/tex]所围成的闭区域.

    • 4

      利用三重积分计算下列由各组曲面所围成的闭区域的形心:[tex=12.857x1.357]p1tbNzhDzGtiHgDLb+0JAo+8TYuNM9pc9uA5nlGlOCs=[/tex]及[tex=3.929x1.429]eXG42LBlVmCe9OBZMR2NwQ==[/tex].