• 2022-06-30
    已知函数[tex=10.929x2.429]LqDon/lJZAKEXw/HyfYzmZl19Isb5lBZk07M3EBPIUqiogjDlff/4sf10+t8lBwWnvFYKjpq41+/mwTlQh3FaG5ZVPAXDb2mzBPZ3OsVdx4=[/tex]在[tex=1.857x1.0]bOlCq/PHWhsSVMaVf7Obdg==[/tex]处可导,求 [tex=1.429x1.214]hGh0CahScTnnSuyOSal1/g==[/tex] .
  • 举一反三