将有关离子依度增大 5 倍, [tex=0.786x1.0]I/kNMtd8YcgkWCrgriW/hA==[/tex]值保持不变的电极反应是
未知类型：{'options': ['[tex=6.5x1.357]d0Lp6nGEzyqHNxCcpWt96hSlrcM5cXqYJj+LQNm/NhU=[/tex]', '[tex=14.571x1.5]fiDIAXLTmhVz6psRp8ayD8rUG10iEAyswo3bJW65Dki2nKKb9REmiH+RprXuiFkpHnUjE55ycEUUx9r9MzKCaw==[/tex]', '[tex=5.857x1.357]bb6eAiLbGV18sfYhk3D3VmZ1pjoQCgP6oGVp+wA1AIs=[/tex]', '[tex=6.714x1.357]wVCmEnB9KbCsilGWboNcLHl1nc4ekRU0aITvYOFEM+Y=[/tex]'], 'type': 102}
未知类型：{'options': ['[tex=6.5x1.357]d0Lp6nGEzyqHNxCcpWt96hSlrcM5cXqYJj+LQNm/NhU=[/tex]', '[tex=14.571x1.5]fiDIAXLTmhVz6psRp8ayD8rUG10iEAyswo3bJW65Dki2nKKb9REmiH+RprXuiFkpHnUjE55ycEUUx9r9MzKCaw==[/tex]', '[tex=5.857x1.357]bb6eAiLbGV18sfYhk3D3VmZ1pjoQCgP6oGVp+wA1AIs=[/tex]', '[tex=6.714x1.357]wVCmEnB9KbCsilGWboNcLHl1nc4ekRU0aITvYOFEM+Y=[/tex]'], 'type': 102}
举一反三
- 将有关离子浓度增大 5 倍, [tex=0.786x1.0]I/kNMtd8YcgkWCrgriW/hA==[/tex] 值保持不变的电极反应是 未知类型：{'options': ['[tex=5.786x1.357]kYWQhjUMlC0WMlfWQaAg/mc9MC0rtMy/3A4CZGPl9CcpJ0DWuimGmZ9PafYmegMu[/tex]', '[tex=13.5x1.5]QEUoJF1kQgL73ycKX9sVlVpNXjLPV1ao89AZ6C3o7uKOmX4SvlSL8xF+qGGrRwBdhuIQA8nXhkayvxIvcxKT8G/b+nPRmA0KOBvhcA9cKbng2FGUT0ijwinPagMb+tx4fRC2vfHPEKRSJ77Po36fpQ==[/tex]', '[tex=5.357x1.214]1QfQ/L7e7Ybqz7/+l580Cf80kC5+4fer8Gc/4beVG8SLsiwdzKNm+nRnJpZtkU/j[/tex]', '[tex=6.143x1.357]xaXcThibTI3wZxi10FYG31t9GKmWthFszzuhuRsMdToqeH/kx6z6NE0Ggk6L/3er[/tex]'], 'type': 102}
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 某人对商品x的需求函数是[tex=5.214x1.214]0m6eBd5eyK0NjuxeKfwtIw==[/tex]，[tex=4.214x1.214]I717YsPbj8Rnym1v2XQ+sFNkUl7mqUsGwbjwjXmy2xc=[/tex]，这里[tex=0.571x1.0]Za328cIB4SeR7rrzY+MM5Q==[/tex]是[tex=0.571x0.786]ZSLOI4fiO1oAbVC5M8IVkA==[/tex]的价格。如果商品x 的价格是0.5元，那么他对商品x的需求价格弹性是 未知类型：{'options': ['-10', '- 1/5', '-1/10', '\xa0- 1/3'], 'type': 102}
- 给定平面图[tex=0.786x1.0]LyvDGollVJ+xwurtsLcn0g==[/tex]如图6.17所示，平面图的面数是（ ）.[img=355x220]178646b659a6f03.png[/img] 未知类型：{'options': ['6', '5', '8', '9'], 'type': 102}