A: 2x-y+8z=12
B: 2x-y+2z=-12
C: 2x+y+2z=12
D: 2x+y+2z=-12
举一反三
- 已知x=1,y=2,z=3,执行下列语句if(x>y) z=x;x=y;y=z;则x,y,z的值分别是 A: x=1,y=2,z=3 B: x=2,y=3,z=1 C: x=2,y=2,z=1 D: x=2,y=3,z=3
- 设A=,且A的特征值为1,2,3,则有() A: x=2,y=4,z=8 B: x=-1,y=4,z∈R C: x=-2,y=2,z∈R D: x=-1,y=4,z=3
- 已知int x=1,y=2,z=3;以下语句执行后x,y,z的值是( ). if(x>y) z=x; x=y; y=z; A: x=1, y=2, z=3 B: x=2, y=3, z=3 C: x=2, y=3, z=1 D: x=2, y=3, z=2
- 设平面过三点A(2,2,3),B(3,4,1),C(-1,6,4),则该平面的方程为() A: 2x-y+8z=12 B: 2x-y+2z=-12 C: 2x+y+2z=12 D: 2x+y+2z=-12
- 以点\( (2, - 1,2) \)求球心,3为半径的球面方程为( ) A: \( {(x + 2)^2} + {(y - 1)^2} + {(z + 2)^2} = 9 \) B: \( {(x + 2)^2} + {(y - 1)^2} + {(z + 2)^2} = 3 \) C: \( {(x - 2)^2} + {(y + 1)^2} + {(z - 2)^2} = 9 \) D: \( {(x - 2)^2} + {(y + 1)^2} + {(z - 2)^2} = 3 \)
内容
- 0
以下方程在空间中表示柱面的是( )。 A: \( {x^2} + {y^2} + {z^2} = 1 \) B: \( z = \sqrt { { x^2} + {y^2}} \) C: \( {x^2} + {y^2} = 4 \) D: \( z = {x^2} + {y^2} \)
- 1
已有定义语句:int x=2,y=4,z=6;if(x>y) z=x;x=y;y=z;执行上述语句后x,y,z的值是____。 A: x=4,y=2,z=2 B: x=4,y=4,z=2 C: x=4,y=6,z=6 D: x=4,y=2,z=6
- 2
9. 已知函数$z=z(x,y)$由${{z}^{3}}-3xyz={{a}^{3}}$确定,则$\frac{{{\partial }^{2}}z}{\partial x\partial y}=$( ) A: $\frac{z({{z}^{4}}-2xy{{z}^{2}}-{{x}^{2}}{{y}^{2}})}{{{({{z}^{2}}-xy)}^{3}}}$ B: $\frac{z({{z}^{4}}-2xy{{z}^{2}}-xy)}{{{({{z}^{2}}-xy)}^{2}}}$ C: $\frac{z({{z}^{3}}-2xyz-{{x}^{2}}{{y}^{2}})}{{{({{z}^{2}}-xy)}^{3}}}$ D: $\frac{z({{z}^{3}}-2xy{{z}^{2}}-{{x}^{2}}y)}{{{({{z}^{2}}-xy)}^{3}}}$
- 3
【单选题】Python中执行赋值语句x, y, z = 1, 2, 3后,再执行z, x, y = y, z, x,变量x、y、z中分别赋值为____。 A. x=1, y=2, z=3 B. x=3, y=1, z=2 C. x=2, y=1, z=3 D. x=3, y=2, z=1
- 4
4.已知二元函数$z(x,y)$满足方程$\frac{{{\partial }^{2}}z}{\partial x\partial y}=x+y$,并且$z(x,0)=x,z(0,y)={{y}^{2}}$,则$z(x,y)=$( ) A: $\frac{1}{2}({{x}^{2}}y-x{{y}^{2}})+{{y}^{2}}+x$ B: $\frac{1}{2}({{x}^{2}}{{y}^{2}}+xy)+{{y}^{2}}+x$ C: ${{x}^{2}}{{y}^{2}}+{{y}^{2}}+x$ D: $\frac{1}{2}({{x}^{2}}y+x{{y}^{2}})+{{y}^{2}}+x$