已知某前向通路的传递函数 (如图所示 )[tex=6.286x2.429]K/no4e1C3aEirAdlJUP45gogUSz/04TLtDNhTaSH900=[/tex]今欲采用负反馈的办法将阶跃响应的调节时间[tex=0.714x1.143]qTrj7KH3ChzmnWtmycMjWSk47VD7pBsYxNEjxfVTnsk=[/tex]减小为原来的[tex=1.286x1.0]GJNMHd4HSsVjtzDdfSsrzw==[/tex]倍，并保证总放大系数不变。试选择 [tex=1.357x1.214]3xQMuPhF0GGEYFjBBuxK4UrEZGmWDilUAzrjMy01J48=[/tex]和[tex=1.143x1.214]K67FhfsE1a1OwcOmEgFBap7hixiZ2p0jJBpYkWOsDRo=[/tex]的值。[img=439x150]17b2f90205f0666.png[/img]

2022-10-31

已知某前向通路的传递函数 (如图所示 )[tex=6.286x2.429]K/no4e1C3aEirAdlJUP45gogUSz/04TLtDNhTaSH900=[/tex]今欲采用负反馈的办法将阶跃响应的调节时间[tex=0.714x1.143]qTrj7KH3ChzmnWtmycMjWSk47VD7pBsYxNEjxfVTnsk=[/tex]减小为原来的[tex=1.286x1.0]GJNMHd4HSsVjtzDdfSsrzw==[/tex]倍，并保证总放大系数不变。试选择 [tex=1.357x1.214]3xQMuPhF0GGEYFjBBuxK4UrEZGmWDilUAzrjMy01J48=[/tex]和[tex=1.143x1.214]K67FhfsE1a1OwcOmEgFBap7hixiZ2p0jJBpYkWOsDRo=[/tex]的值。[img=439x150]17b2f90205f0666.png[/img]

答案：

解：[tex=22.571x2.929]vJ+YJqfkh4Lm7o9z15ZC6VwKASgUQJ37FvEQ2vN7Fyr6WDMk9ygKfof3ui2uwKf7SoPpMEViadS+MjXfpcDr+srSISh2MOuH3Bkuh4ad337Fa4u+y5XrpSzp14T8Q7r0hxOhtP58HIyiDDR1Mqj2hPTzK241XTjWiccnpzDEjN7sv3Y+Hb4Nm/bt6TJ5wtlASpWnwWF0rhVBWIdJDn5vW+DOP2e9MT0BWYBw5u2aHkYQY6SIgV0yXH3lYd9iToz6ijQTqggfreDrsWUDRMJjrOigC1P6ujQoVoyxjyFmJt00EiFYIPU1el3HSdzTypHDSMbfNyFF1yd+4xRnK8L/6vO4vfLp3ABEjoEOn4IbsGHM6PfOR35PovmmoXj+u+zk[/tex][tex=14.929x4.5]fnpmC2J6JmQBLyo5NmGAzy2XMsPNklGf5vaj7dmaAg81uFx52eaowtTSW1slQFGJaFEm2+VxuZ28SWi0Hpm3+MwTkViyZ/6SBicE1/JS4dTwnHyJz+eddJ0fTBGb8SSQTmHKSeBRLvCsqmR21ukBrZtEp+BTKxPrYZK4fIgNL3Mdwa59j9mfEfUFy5hj1PuIQrq3RLWAJn4hcXULdlzgn/Vtww7FpljbmXmranEr9uyFeIHyAveHjd8Iz9njZ0HsNd81MzlRA9EhlVeIuhAc3xYLSAig5YI17RCKmOGB6T4=[/tex]解得：[tex=7.286x1.214]jEBiTKfn4JpNaXJdmxCl/tvuSVu05q+Ed1M5H7Fzp7heeSkLtxj0g8ny6C7NvG8JW35s4u5f83BKDYFxEEjSkA==[/tex]

举一反三

内容

0
由非空集合X的所有子集构成的集合称为X的幂集，记作[tex=1.143x1.214]6fgP1j+0v37iZFMJocAU+g==[/tex].（1）设X={a,b,c}，求[tex=1.143x1.214]6fgP1j+0v37iZFMJocAU+g==[/tex].（2）设X是由n个元素组成的有限集，证明[tex=1.143x1.214]6fgP1j+0v37iZFMJocAU+g==[/tex]中含有[tex=1.0x1.0]j//x0/Z+ltpf5R8ThFOpMA==[/tex]个元素.
1
若:(1)函数 f(x)在点[tex=0.929x1.0]cjoIbYuE/p4IqfLA8eA4ZA==[/tex]有导数,而函数g(x)在此点没有导数;(2)函数f(x)和g(x)二者在点[tex=0.929x1.0]cjoIbYuE/p4IqfLA8eA4ZA==[/tex]都没有导数,可否断定它们的和[tex=7.214x1.357]oX568MWmpJJk2c1dN8FEzQ==[/tex]在点[tex=2.286x1.0]DSJKaWfJALImFxxTg/8qhA==[/tex]没有导数?
2
[tex=2.214x1.0]Z8GWW72u+MH/mjafnp+83A==[/tex]丙酮酸经过丙酮酸脱氢酶系和柠檬酸循环产生[tex=4.0x1.214]EPDWVFNjIR8daNoozaWRDg==[/tex],生成的[tex=3.214x1.0]1AqDCKqjaAug6buHS5Z0tQ==[/tex]、[tex=3.429x1.214]HYAn2+I9AZQLWcA3ajoPaw==[/tex]和[tex=2.143x1.0]qQANfGnLx7pE5mcaEibuNg==[/tex](或[tex=2.071x1.0]YGdeb/NAM7yg+XY6SY16Fg==[/tex])的摩尔比是( )。未知类型：{'options': ['3:2:0', '4:2:1', '4:1:1', '3:1:1', '2: 2:2'], 'type': 102}
3
已知[tex=10.786x1.357]oPxEQGciaJq0uWonaJqXssvTKx2aAMqoshLd51U2O4M=[/tex]，若[tex=2.0x1.214]IENxQEh5u4RdnCaqHm72Xg==[/tex]相互独立，则[tex=3.0x1.357]cl60lRnHnAb2Fyha9FYNvw==[/tex] A: 1/2 B: 1/3 C: 2/3 D: 3/4
4
对于以下两种情形:(1)x为自变量,(2)x为中间变量,求函数[tex=2.214x1.214]sy9gaFRMGlrH59gm9bWSDg==[/tex]的[tex=1.5x1.429]5W5tOYbJ+LlsRP2dMsi4byxwtjvvL/3u7NEzPV5PWp0=[/tex]