• 2022-10-27
    某理想气体的[tex=4.357x2.429]P0JATRXCF1+0a5gx9gidmX2q20S0kST2kEvzI3OdZ+I=[/tex]。今有该气体[tex=2.143x1.0]FOMa81Ky/512Qvz0sNgyTw==[/tex],在恒压下温度降低[tex=2.143x1.071]915en9rYOIT4icC6pGJjlw==[/tex]。求过程的[tex=4.143x1.214]X9hQghHAOXJmfRutTnOF5w==[/tex]和[tex=1.714x1.0]GAz8dzzwSgrgCCYLVxtjuQ==[/tex]。
  • 解:恒压过程 [tex=16.286x3.071]a0s3MH7cLIdmiBRR0YN065K66/0C7sxZyNKbDkjZ2wmQp5FfBPNQvIsvtu1jAtiOhOSwc91kzWu24AR5/GF2N0v3NawWIkX8FuT2U9VOJws9/CVCyEsFo96T7nTG7Ur6XcZOhdbn7BCEdZQ/lAl3IJ8tdrsOdIkxEmXoVmwbG0FTdsJxvtuFTGqLE9ZDbfvyVTl8CJeBjA7U9AM5mji9hQ==[/tex]由于理想气体下热力学能只与温度有关,所以[tex=19.286x3.214]a0s3MH7cLIdmiBRR0YN068TFIYjVnmrGsnL27sIM8jIb7yz+DkaKK3I5jH9nMylbVKWlBhwOxSJNEB9WieEtso68QOtqGyPR1H4VaLrZPOFR4csX0cEKTAzUWaOhlW3cESGM11mf+KFrRS3+kTn3uJfO/lG0EtLtQB/NG8P0g6Nhu1rmtCAUxBb+TEgiETNGxgdtYC5dQPh45+4y+yg+2w==[/tex][tex=18.5x1.357]QsHopdtPV/VFGLoQGF/z4n1DHLEDE95JGJzk09ASIoVco+aHz1rHxI7yyy8VwANcCKRSlLpQFUPeM9EjFAaq8ViNN0hNQBBipnYuXiZS1Pw=[/tex][tex=10.071x1.286]uVsskGgbAFh5P/delgs7Gze6+uAomOZO+JibQYmFfwX/Xl1E/cmywRozia8QWUSB[/tex]

    举一反三

    内容

    • 0

      对于以下两种情形:(1)x为自变量,(2)x为中间变量,求函数[tex=2.214x1.214]sy9gaFRMGlrH59gm9bWSDg==[/tex]的[tex=1.5x1.429]5W5tOYbJ+LlsRP2dMsi4byxwtjvvL/3u7NEzPV5PWp0=[/tex]

    • 1

      求函数[tex=3.286x1.429]kdT+eIE7CHPynuN6CaN40g==[/tex](抛物线)隐函数的导数[tex=1.071x1.429]BUw1BPFU3fsJlAl/vt9M9w==[/tex]当x=2与y=4及当x=2与y=0时,[tex=0.786x1.357]Hq6bf3CacUy07X+VImUMaA==[/tex]等于什么?

    • 2

      若:(1)函数 f(x)在点[tex=3.714x1.357]7VByCIzkNySq3s2l9I6f5zccNJDeV+6SQrVr3iwjgB0=[/tex]有导数,而函数g(x)在点[tex=2.286x1.0]DSJKaWfJALImFxxTg/8qhA==[/tex]没有导数;(2)函数f(x)在点[tex=3.714x1.357]7VByCIzkNySq3s2l9I6f5zccNJDeV+6SQrVr3iwjgB0=[/tex]没有导数,而函数g(x)在点[tex=2.286x1.0]DSJKaWfJALImFxxTg/8qhA==[/tex]有导数;(3)函数f(x)在点[tex=3.714x1.357]7VByCIzkNySq3s2l9I6f5zccNJDeV+6SQrVr3iwjgB0=[/tex]没有导数及函数g(x)在点[tex=2.286x1.0]DSJKaWfJALImFxxTg/8qhA==[/tex]没有导数,则函数[tex=5.643x1.357]GmtX7Vop79exGU/rpqXUYw==[/tex]在已知点[tex=2.286x1.0]DSJKaWfJALImFxxTg/8qhA==[/tex]的可微性怎样?

    • 3

      求下列函数的导函数:(1) [tex=5.0x2.357]X/CieCDGJ7iPQ3YFWuscHxHrcIE/dPFa9tFyiJXze8A=[/tex](2)[tex=6.643x1.714]Oj74y/L+OxY81QME5JWMcl+7PZ2FGQswwvjgVhjq1Dmb6dBU0oAjZBW7eFBVjqo6[/tex]

    • 4

      求柱面 [tex=3.929x1.429]/zgqabtImeIaKGhfpDlfIA==[/tex] 与三张平面 x =0, y = x , z =0 所围的在第一卦限的立体的体积。