A: 2(1-x2)+C
B: -2(1-x2)+C
C: -1/2(1-x 2 ) 2 +C
D: 1/2(1-x 2 ) 2 +C
举一反三
- 若∫f(x)dx=x2+c,则∫xf(1-x2)dx=( ). A: 2(1-x2)2+c B: -2(1-x2)2+c C: -1/2(1-x 2 ) 2 +C D: 1/2(1-x 2 ) 2 +C
- 若\( \int {f(x)dx = {x^2} + C} \),则\( \int {xf(1 - {x^2})dx = } \)( ) A: \( 2{(1 - {x^2})^2} + C \) B: \( - {1 \over 2}{(1 - {x^2})^2} + C \) C: \( {1 \over 2}{(1 - {x^2})^2} + C \) D: \( - 2{(1 - {x^2})^2} + C \)
- 若不定积分∫f(x)dx=x2+c,则不定积分∫xf(1-x2)dx=().(A)-2(1-x2)2+c(B)2(1-x2)2+c(C)(D)若不定积分∫f(x)dx=x2+c,则不定积分∫xf(1-x2)dx=( ).
- 17e0b849b7d64bd.jpg,计算[img=19x34]17e0ab14a855463.jpg[/img]实验命令为(). A: syms x;f=diff(asinsqrt(x))f=1/2/x^(1/2)/(1-x)^(1/2) B: f=diff(asin(sqrt(x)))f=1/2/x^(1/2)/(1-x)^(1/2) C: syms x;diff(asin(sqrt(x)))f=1/2/x^(1/2)/(1-x)^(1/2)
- 17da42840675a6d.jpg,计算[img=19x34]17da4275482315f.jpg[/img]实验命令为(). A: syms x;f=diff(asinsqrt(x))f=1/2/x^(1/2)/(1-x)^(1/2) B: f=diff(asin(sqrt(x)))f=1/2/x^(1/2)/(1-x)^(1/2) C: syms x;diff(asin(sqrt(x)))f=1/2/x^(1/2)/(1-x)^(1/2)
内容
- 0
∫xe^(x^2)dx=( ) A: 1/2(e^(x^2)) B: 1/2(e^(x^2))+C C: -1/2(e^(x^2)) D: -1/2(e^(x^2))十C
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【单选题】二元 溶液 , T, P 一定时 ,Gibbs—Duhem 方程的正确形式是 (). A. X 1 dlnγ 1 /dX 1 + X 2 dlnγ 2 /dX 2 = 0 B. X 1 dlnγ 1 /dX 1 + X 2 dlnγ 2 /dX 1 = 0 C. X 1 dlnγ 1 /dX 2 + X 2 dlnγ 2 /dX 1 = 0 D. X 1 dlnγ 1 /dX 1 – X 2 dlnγ 2 /dX 1 = 0
- 2
17e0b849d3a4a3b.jpg,计算[img=19x34]17e0ab14a855463.jpg[/img]的实验命令为( ). A: syms x; f=diff((1+sin(x)^2)/cos(x),1)f=2*sin(x) + (sin(x)*(sin(x)^2 + 1))/cos(x)^2 B: f=diff((1+sinx^2)/cosx,1)f=1/2/x^(1/2)/(1-x)^(1/2) C: syms x;f=diff((1+sinx^2)/cosx,1)f=2*sin(x) + (sin(x)*(sin(x)^2 + 1))/cos(x)^2
- 3
下列积分中()不是广义积分。 A: \( \int_0^1 { { x \over {\sqrt {1 - {x^2}} }}dx} \) B: \( \int_0^2 { { 1 \over { { {\left( {1 - x} \right)}^2}}}dx} \) C: \( \int_0^1 { { 1 \over { { x^2}}}dx} \) D: \( \int_0^1 { { 1 \over { { x^2} - 4}}dx} \)
- 4
下列四个积分中,()是广义积分。 A: \( \int_0^2 { { 1 \over { { {(3 - x)}^2}}}dx} \) B: \( \int_0^6 { { {(x - 4)}^{ - {2 \over 3}}}dx} \) C: \( \int_0^1 { { 1 \over {1 + {x^2}}}dx} \) D: \( \int_1^2 { { 1 \over { { x^2}}}dx} \)