• 2022-06-04
    已知图[tex=1.357x1.357]TWUgLpDrEXIKICMuiEQPjw==[/tex]所示系统的单位阶跃响应曲线图 [tex=1.214x1.357]vzdGmXlbw83hTiK2SebvEA==[/tex] , 试确定[tex=1.143x1.214]ezZu/Yi5aSD6qMrBwkUbeQ==[/tex], [tex=1.143x1.214]+w6jxlHC+fx52efQY3vetA==[/tex]和[tex=0.5x0.786]jd4+RydyOqGh1cA2RJ/ovQ==[/tex]的数值。[img=655x228]17b300b6702d6a8.png[/img]
  • 解: 由系统阶跃响应曲线有[tex=10.643x5.786]GE56u9QCDTqcLxZ66HADyquFRrgfKs9PVNPfMggbKM6O6JZLOM3Jb2/x5gCDeE0O3s1tniN5qzRhhrZUY/kNhsaGCU6rR4PVHKGfFlppcLWi1DlUvCZogWu/4ekbiMTojIOM34hHcwM+Ikda3BaYtC0aiTqw8N/RXcqbZsX+9Vo=[/tex]系统闭环传递函数为[tex=14.5x2.786]v8tTu4fIZnLaNaGjonXb+ZD7sUfKMTaYwIiALuOL89ctOuZV+3WxJ6Tf9hneHmOKYtL1jJKt5/I2a6GtpHiar+ecHtw5SXSz2zYKDas0YDPeorVvN4gOMZjBQuKMWX/N4kykpletTkWfIX0ImJ1XHkJ0y9RoviFYkffq2I5l86SklpF/VzkwKa0gxSrYk42in0X6JhHYPV1fgsHPLDFlJzzrDNRgqgHYsGKwei6AGltyLCO+lC1goSfSnpC8Dny28HxIoHArOs4a33lF/cEnA7nTexgigKQtuS4C5U4hlwtYuOU+1VnbzXujJSV45mBl[/tex]由[tex=12.786x4.5]7EJHVCtO2IWq3KpdB+jQskavlHFV/CoACI5XczTxzYlVG7z8b9GgsuQ5nql++qcNEvXU+4wyM4qR+ZOmkYStZLU2zBOq8Wtpv//R5fktmGIJKnyw2nhhB9UFnd4SHlC9yr2GFMduSE1ZUIr93SvOgdsVTXVShW5uABDm5i5yVOln2BHqOKETda8wxRPqih2uVIiE+sblpbBJRoERnkctq2koqVBGe0CZ8nPDFugCPW8dAqmZBFUcKm6Wmq/9mW2l[/tex]联立求解得 [tex=5.857x2.786]7EJHVCtO2IWq3KpdB+jQshmhK32s6wqpODGhSJXHfGnDiTS6HufCAociaZfQ8j0DPO8OoYVFzU+2ZkErUgZetz8Z2Uf6bbdjPObVuxfAq+o=[/tex]由式[tex=9.0x3.357]0yVUOzg25tj1fTLTJKrrDAztlCrG5h0+aYbnLpdm5+YS81C8i57Lnbdq5tWo6PPmqGhbaPsf+dRzR5dbU4lyAxj9rcxb6PmfVp4iGBy/rYUE5cR2TN/2TUPdlqv7oL/mEM6nj5eLousk5NH+1yLXtBVi35EStOM8BOLo4CdfOyKHLDy50SBIhuWWi6I0uSPH[/tex]另外[tex=18.929x2.571]4WNPyWahXJjbuxHTCP+9ygme32N06euaPo60rRFVQMXkqaewqhBPzZx+GxrGPMnpFsOF9q4duysCu8kuvq9cMy6E21cOqAV/tSKPO214RZeBK8MBL5e56OKtvHVEUxt9loYP/Ik16kwJWgfM6gv7yYAQNoeSX97NI4u+bNTyzkMwwcgG5fRGwU0rsYdArrG5ZDpKuz+UX2ghy/Yg8AE4+S11jrkEF0u2J57F2eiRESfhnRcrsaN2pFSQKmS9ljw2/r6aG8Gk2NCEJoank1zvSY/6D9paASweDBJrEZToMd2dEVfwymog6BSvarPUlP/b[/tex]

    内容

    • 0

      设[tex=5.929x1.071]gAFI4ZzNAmjFfJAphmTsRQ==[/tex],若[tex=7.786x1.357]09fTpcwFMVcu1qrv9hyVbjaVP6Nu0Q7b0o9JCaEhfzk=[/tex],[tex=7.786x1.357]17Fg+KbtgLZdNaerla1J+g==[/tex],[tex=7.714x1.357]GzWWzGNDry0+/hdju2Gv5Q==[/tex],那么[tex=0.571x0.786]/uIIzJZ/1DPgc5sOsRpAXQ==[/tex],[tex=0.571x1.0]Tr41q2//n6lfFMLRmh8s0w==[/tex],[tex=0.5x0.786]rGd4FFr4Zsu+cuz6gxITMA==[/tex]的大小关系为 A: x<y<Z B: y<z<x C: z<x<y D: z<y<x E: 不能确定

    • 1

      比较下列化合物硝化反应速率, 由快到慢排列次序[tex=1.357x1.357]TWUgLpDrEXIKICMuiEQPjw==[/tex][img=79x84]17aa428e401adf9.png[/img]  [tex=1.214x1.357]vzdGmXlbw83hTiK2SebvEA==[/tex][img=77x123]17aa42945cbd482.png[/img]  [tex=1.214x1.357]zs4t7aUJaV7q8Vd+b4EZVA==[/tex][img=86x127]17aa429a639ecf5.png[/img]

    • 2

      求如图所示的图[tex=1.143x1.214]tVkSXDTbP2YDKnpeqXNXXg==[/tex]和[tex=1.143x1.214]z/iyGGP+DXie1qfllHTsVg==[/tex]的并图。图[tex=1.143x1.214]tVkSXDTbP2YDKnpeqXNXXg==[/tex]:[img=213x150]179b699edf53e45.png[/img]图[tex=1.143x1.214]z/iyGGP+DXie1qfllHTsVg==[/tex]:[img=205x161]179b69a58cdd9e2.png[/img]

    • 3

      将下列化合物按沸点高低排列成序:[tex=1.357x1.357]TWUgLpDrEXIKICMuiEQPjw==[/tex]正己醇  [tex=1.214x1.357]vzdGmXlbw83hTiK2SebvEA==[/tex]苯酚  [tex=1.214x1.357]zs4t7aUJaV7q8Vd+b4EZVA==[/tex]正丙醚  [tex=1.357x1.357]YP0FHP8gDdcjJmICkuaGEg==[/tex]乙烷

    • 4

      题图[tex=1.357x1.357]TWUgLpDrEXIKICMuiEQPjw==[/tex]电路中,已知 [tex=5.143x1.5]vPhZr9VNdE+TTQcqWDq84zymXuq3wK3Lqwpr7RBEIuX1AAFwxirB9rZpU3YFOQjc[/tex], 其 [tex=2.071x1.357]T3ye52AJDdK9KKVrGZhk7fU4ldrm1S+fCme+H/3IBmI=[/tex] 波形如图 [tex=1.357x1.357]fjWMaYcefEESw2uiWhETZw==[/tex] 所示,试求 [tex=1.929x1.357]fpKeggpLJzPWzKQlJQOF4j7NQEGK3AtfsHATDyDtz7I=[/tex]。[img=661x237]179a2d3710d1ae5.png[/img]