• 2022-06-06
    设[tex=4.643x1.357]3Td6+uCAktUQOopEGtH1MA==[/tex](1)求[tex=23.786x1.357]NmwJpo7pEh4XYT4W8FKDbpmyO3tXsyuMMoSuIbNjHpMSFAQr9KxVjlxxiq+RUrG1[/tex](2)确定[tex=0.5x0.786]EL0hSqs6jZBGdsmH7TMShQ==[/tex],使得[tex=8.214x1.357]ArnjGiniSZwTp6bmdg0hWUPPOMlbiZ+0kJYHgcB54zM=[/tex];(3)设[tex=0.571x1.0]TcM6B5Wrs5vy9dWrxRPSdg==[/tex]满足[tex=7.0x1.357]Mbgw6HlDthmIZy4WQWLsVw==[/tex],问[tex=0.571x1.0]TcM6B5Wrs5vy9dWrxRPSdg==[/tex]至多为多少?
  • 解 (1)由已知所求概率分别为[tex=30.929x15.929]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[/tex](2) 因为[tex=10.143x1.357]vxAmLI7GWXhIkjwthZ7QUtmhYWlQWdrjRDXDb79UfSU=[/tex],欲使[tex=8.857x1.357]2NOKwHc2SRZVHcKFrCeoc0vv9jc5USNFUTc1Q7WvsJw=[/tex], 只 要[tex=5.714x2.357]5utQg0whBpDUjVfENtxB9fGnIHbtzIljgnPziiLzEVQ=[/tex],即[tex=7.286x2.786]6rHaf+ymKrldcTnxWOtOWU9sQPKg75ttuokwqPiQLEcW3g8UnlRLHNMJvEhZFsrL[/tex],故[tex=1.714x1.0]9EFnzVmsR2c+lc1fcdf3Ew==[/tex].(3) 因为[tex=19.5x2.786]rqvCgHT+wBgvxzRkXK+4/kI5EoeNTVNHy8j2ur5DIqOTKGeFn5bAtt5JoQCAZE6yBLaVK3U3m2AHFb/yxLP3NUokQ5DO6jrSoGXhdeV333JiiWMufmQpGzJMzW+qlkNP[/tex],要使得 [tex=7.0x1.357]8tFGk6vQAYJb/F3WMzpixJEqJWAFX6p941fuZqLehCQ=[/tex]只要[tex=8.571x2.786]OZuQN8uzsoK/KyI8K1Y7m9N5YB6nMzkwdQqx5N1B30LxRuH7D0lf86LPvB0iq6Dh[/tex]即[tex=7.357x2.786]6rHaf+ymKrldcTnxWOtOWZU1AzHqrUkh57Kdc89hZNePhdxFgZ1yYIzwd6QWWfwA[/tex]也就是[tex=7.357x2.786]6rHaf+ymKrldcTnxWOtOWcH20GlNG9BYX3o2TFedtAnFs7xxoKI41BWgis+oA1gd[/tex]查表[tex=14.429x1.357]DFvXz51Wbzadq69+ZrCw8unkp3n7bZL7U/Nd5zqB+YL/wSoT0cfMLZxOjNub/mUg[/tex]因此[tex=5.214x2.429]RFQ/evqBdUnX92wCqCumTIw7wzWIM3uCou0K26YGxF0=[/tex],[tex=3.643x1.143]9pnzeY0Q35eqvDVIrpSJWw==[/tex].

    举一反三

    内容

    • 0

      set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为? A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}

    • 1

      设[tex=5.929x1.071]gAFI4ZzNAmjFfJAphmTsRQ==[/tex],若[tex=7.786x1.357]09fTpcwFMVcu1qrv9hyVbjaVP6Nu0Q7b0o9JCaEhfzk=[/tex],[tex=7.786x1.357]17Fg+KbtgLZdNaerla1J+g==[/tex],[tex=7.714x1.357]GzWWzGNDry0+/hdju2Gv5Q==[/tex],那么[tex=0.571x0.786]/uIIzJZ/1DPgc5sOsRpAXQ==[/tex],[tex=0.571x1.0]Tr41q2//n6lfFMLRmh8s0w==[/tex],[tex=0.5x0.786]rGd4FFr4Zsu+cuz6gxITMA==[/tex]的大小关系为 A: x<y<Z B: y<z<x C: z<x<y D: z<y<x E: 不能确定

    • 2

      某人对商品x的需求函数是[tex=5.214x1.214]0m6eBd5eyK0NjuxeKfwtIw==[/tex],[tex=4.214x1.214]I717YsPbj8Rnym1v2XQ+sFNkUl7mqUsGwbjwjXmy2xc=[/tex],这里[tex=0.571x1.0]Za328cIB4SeR7rrzY+MM5Q==[/tex]是[tex=0.571x0.786]ZSLOI4fiO1oAbVC5M8IVkA==[/tex]的价格。如果商品x 的价格是0.5元,那么他对商品x的需求价格弹性是 未知类型:{'options': ['-10', '- 1/5', '-1/10', '\xa0- 1/3'], 'type': 102}

    • 3

      7个变量出现在计算机程序的循环中。这些变量以及必须保存它们的计算步骤是: [tex=0.429x0.929]r8lLiDb0KHTzu/2y/Au89w==[/tex]:步骤1~6;[tex=0.643x0.786]cnVwa8IjZzNSEmAUXJ8VCQ==[/tex]:步骤2;[tex=0.5x0.786]GWrvJtODhYOBa2bpkSPSFQ==[/tex]:步骤2~4;[tex=0.786x0.786]44SGfA2gQ2VZlXa1QKZD0Q==[/tex]:步骤1,3和5;[tex=0.571x0.786]c5VsltFnl9nO0qB/vNKOWA==[/tex]:步骤1和6;[tex=0.5x1.0]iwXm0SwS+lfupyC0IyH8yQ==[/tex]:步骤3~6;以及[tex=0.5x0.786]gdMkE6SnyZedYLxpUxdkaQ==[/tex]:步骤4和5。在执行期间需要多少个不同的变址寄存器来保存这些变量?

    • 4

      下列函数是哪些函数复合而成的?(1)[tex=4.214x1.286]6PuLCl/TwscTl61WSePGog==[/tex];(2)[tex=5.214x1.286]+mZ2Cm2OprRKGTGg0iqmyZx+4lZ796PxrSQNx30R9UU=[/tex];(3)[tex=4.214x1.357]jTbrMH55vzOFOJlLSnfh103OHFmRhIjXZGzPnfweOX0=[/tex];(4)[tex=6.071x1.286]W2A0mViHY0pK74wEByr6ED5K+AKV/pxHaeQdYGQBxwc=[/tex];(5)[tex=6.714x1.429]8up/G1s+GteD9ejcGkFVmYl3TTtTik5kuwrPDCv0JkbGIWyY33cnaw7XtBiPcSnh[/tex];(6)[tex=5.714x1.286]APaFs2rWyubdkzLcUVVxVJSSAsLEOtXn4KjnToE2BQA=[/tex];