• 2022-06-16
    设二维随机变量[tex=2.786x1.286]AG5D6gU/evQZlfwisXgzYw==[/tex]的联合密度函数为[p=align:center][tex=15.786x3.643]lJblPB9MNpIrc6Sy3BdmFeZj3i1/SIQqtc8pMJ8ekw0hpO2JWjN0KbCNGW8p7yRliuhj4gEfxKVKP0sL93PRo5jyEZZ6oxEqRp+wTTwwCB/5Jf4bZ/9nPNisFlUzHOxo[/tex]求常数[tex=0.571x1.286]mRKL/orzOudCEARA8qn3Kw==[/tex]和联合分布函数[tex=3.0x1.286]GOR0R/NCj/M/hw3l3obOPw==[/tex].
  • 解 根据联合密度函数的规范性,有[p=align:center][tex=26.857x2.429]84FpKOFCerrpb90b4nq0uTQFINaY06e/1j9ZoZ7noVMUq4OZJjPzj2hKbUX336zBAbuPeyHkUJefcpyf1VsuusXmfpPyWIoAY2/kzfCK8n+p+QPBll59ILlAvptXjLl+kv4pYsgcBljr6UgHZvVkB6w8wQL2kPq9qxlnDtMfQ9KSqP4VP6mm3IkPMX/LXUHvrfyqJrBdB575ukEGHCvvKA==[/tex]由此求得 [tex=2.357x1.286]vwhiGUP1olhsMwF/I4QeMw==[/tex] , 且  [tex=2.786x1.286]wsm6hZKLwoHLmpiSvjoPLA==[/tex]  的联合分布函数为[p=align:center][tex=20.714x8.929]e+K8qVo79wATTTZFrc1V8UyQsPKQ1/nI/QQw5HryEWCTQ8CvjqmQhX6cp/+bdJQ2YfRVzXTTiieERMs0/lxrvrRLCSIVTy9jEo7XCwhJY986SjsdiYWpAYZBRE5HOs635prXuG3NAVyAh91mi3YLJxxe1Q0JxSQ1RobKCQlp3O3NU7dmjikuBn3Sa0/vS2UVVdh8lUcnBXnyvqcyHWquEuwsNxx2kfZmTpy+CD55ymedXPzUw1xoP5LNrFKcJTRq9aOx3iOVfw8rCHcc4AVGkLWxg2GECxOyNv+COCgmFjA/pF68JILyShkXW3Jvpt6+HH61qmDGiJvUbwEzNtVebIeXJeOEI6koGo73E3YY1ofSiFiV7GEiuCDymBO6zMLX4AdRqm2JEJ3nTeClAODs4Ac8id+8dkF10kES4JwSYtE=[/tex]

    举一反三

    内容

    • 0

      >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']

    • 1

      【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=

    • 2

      设二维随机变量 [tex=2.786x1.286]wsm6hZKLwoHLmpiSvjoPLA==[/tex]  的联合密度函数为[p=align:center][tex=15.571x4.786]lJblPB9MNpIrc6Sy3BdmFXJ0yfI4z+iB1nKJ7ROgWqwW7RfhYrJD2clUF+Zi5Z5Vj03Az45w8YqQA9BOPr6Gx2H3LLS1ZwZydXnPAMjYEP1naG7dmgkBfuhE6Rak1UqYwGVgQWserSotntBbc7vVqg==[/tex]求[tex=3.714x1.286]R3Y9cXFg+UXi4JPn32+gxA==[/tex]的密度函数.

    • 3

      以下程序的输出结果是() main( ) { int i , x[3][3]={9 , 8 , 7 , 6 , 5 , 4 , 3 , 2 , 1} , *p=&x[1][1] ; for(i=0 ; i<4 ; i+=2) printf("%d " , p[i]) ;

    • 4

      设二维随机变量[tex=2.786x1.286]AG5D6gU/evQZlfwisXgzYw==[/tex]的联合密度函数为[tex=17.643x3.643]lJblPB9MNpIrc6Sy3BdmFY0caaqrhqD4gwf+7QHot1rtfDUbpZzDYIJpx7nOrjGBNlWIGzSwLVMYVwJL3s4HaWBEvp77HHTqJ+MR3njJsBk=[/tex]求  [tex=4.929x1.286]bstb6Acm/GnARrPc8f1uPw==[/tex]  的密度函数.