• 2022-06-18
    设[tex=3.571x1.214]Wpf4qiH41W2R7hUv1LWig+E5o4puQ2RJlARfI+eCqm8=[/tex],证明:如果矩阵[tex=2.0x1.214]dH+6mcnQkCGsI4eUwNRa1w==[/tex]的每一个[tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex]阶主子式都为零,则[tex=4.786x1.071]uqh+oOvD2P9iqZ7dD7XO1KKN/uGvRiqYP9oeyuLdVrw=[/tex]。
  • 证:由[tex=6.643x1.214]DwJwpykEZS4juOm3SZANdg==[/tex]公式,[tex=11.0x2.786]NmGAzUwMsB3c37tpoLiuS2RcZgk5cfh9VtB0CHTRAQFPNpsACLLe0xBRs95UJq7je5V+SQKmzRcJNF4vrLBfpNhu34kc4gb4Oix+Pbk5dJZY33QObddOUFqMlprQkt1iBTM9KUJvZBXi/99iw+/4fpMn/KN/aYOv83n1H879VTk=[/tex][tex=27.0x3.643]ACpO+Qwyibk67U/b3k9hX53sUNfH/gOTptEc+arnsKwu54qh4Ss9XzgGEHM1iWn1ZL7KGue2Ji2Iyg82BdSlv5HDTQYNe8WOPBIFjvIewUy0xB1O/y2Cdqr5SRkR9Ywl/WcBSTvN+sY74txuX+PU1IyGA7viHhW9BYzLo+8EHnKrcVVTUhanaesPWfVzgRPn5F5phVTkKG62Y/f0mIayx97u13wF89Js05kyCjb4rgqbuQkuJJa9S5+VJCRXseeskOZ7JDclk7CUThDmPc6XX8rtR9BJ51tCP+IaXfJmEk0CYYgKrlyZdpW00QN2NIid[/tex][tex=20.429x3.714]Bu/ejfEtjLwxJvuxglokfZkbU97g1j1FPIfH8KMieSRuylCngbFN530GprLeD3rp8EAMqZpwAtlEhgT9LnWrgOWzrktb9Radc/LsnhoMJ5an4T/O4kFaUjiLpnfjZ8O60/F+mAZXRGJMpOVmqjEToLLpxBAxFKDzSn0GQoFzjyIZM3UJoFFYJQKTpf1nfDCrF3Nw6RRaIusuN+/LwDbkp8VWaOHJJY1v7pK1SKb0ja8=[/tex]我们知[tex=11.429x2.786]UCm8jNMlvFhFafPwI5jZtZp6Wulll8WlH28LjOZASkGeNL7uF84g9zpfhh0AK85mTx7ibgZBHCLo/McgofBo0t95d9ZhQoJuQHV4AmV6XW5+ml8Ng8hFNhhAc9WdMsmS5P7Oo44QVCqaxCaCdBtWXN6Gk/VOa0ioNKZQo9H5qR0=[/tex],即[tex=0.786x1.0]b4HkKtHXeHofHX/gJc8Agg==[/tex]的[tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex]阶子式均为零,故[tex=4.786x1.071]k8PvTJe4iQVkvPfhUhxDGEhW5tmtk2l6FIykzAnfUcg=[/tex]。

    举一反三

    内容

    • 0

      证明:前[tex=0.643x0.786]/he/ol8BkDuTTL9yMPtH4Q==[/tex]个自然数之和的个位数码不能是 2、4、7、9

    • 1

      求解下列矩阵对策,其中赢得矩阵 [tex=0.786x1.0]b4HkKtHXeHofHX/gJc8Agg==[/tex] 为$\left[\begin{array}{llll}2 & 7 & 2 & 1 \\ 2 & 2 & 3 & 4 \\ 3 & 5 & 4 & 4 \\ 2 & 3 & 1 & 6\end{array}\right]$

    • 2

      已知[tex=10.786x1.357]oPxEQGciaJq0uWonaJqXssvTKx2aAMqoshLd51U2O4M=[/tex],若[tex=2.0x1.214]IENxQEh5u4RdnCaqHm72Xg==[/tex]相互独立,则[tex=3.0x1.357]cl60lRnHnAb2Fyha9FYNvw==[/tex] A: 1/2 B: 1/3 C: 2/3 D: 3/4

    • 3

      设[tex=0.857x1.0]FfIhW8W8Jb8XV2jfmtoNZA==[/tex]是一个奇数. 证明:[tex=1.071x1.0]YIRGFczM5Qfvzt6XjJW6wQ==[/tex]阶群[tex=0.786x1.0]LyvDGollVJ+xwurtsLcn0g==[/tex]必有[tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex]阶子群.

    • 4

      设[tex=2.0x1.357]JGIimJ0gsQwNToblSlzsJw==[/tex]是一个非常数的多项式. 如果[tex=2.0x1.357]JGIimJ0gsQwNToblSlzsJw==[/tex] 有 [tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex] 个不同的实零点,证明 :对于任何的实常数 [tex=7.143x1.429]lIRnvX9cohtjOwZSRZxprgL5cKVou2Ti2nLJAA2dS2o=[/tex] 至少有 [tex=0.571x1.0]rFc/sfAAuCOtzhevhoREeA==[/tex]个不同的零点.