• 2022-06-18
    \(x =\)______ 是函数\(f(x) = \left\{ {\matrix{ {x\quad , - 1 \le x \le 1} \cr {1\quad ,x 1} \cr } } \right.\)的跳跃间断点。
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    举一反三

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    • 0

      下列函数中,( )是初等函数. A: \(y = \arcsin ({x^2} + 2)\) B: \(f(x) = \left\{ \matrix{ 0,x \notin Q \ \cr 1,x \in Q \ \cr} \right.\) C: \(y = \sqrt { - {x^2} + 1} \) D: \(f(x) = \left\{ \matrix{ {x^2},0 \le x < 1 \ \cr x + 1,x > 1 \ \cr} \right.\)

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      \(a = 2\)时,函数\(f(x) = \left\{ {\matrix{ {a\quad \quad ,x = 0} \cr {2 { { \sin x} \over x},x \ne 0} \cr } } \right.\)在\(x = 0\)处连续。( )

    • 2

      函数\(f(x) = \left\{ {\matrix{ { { x^2}\sin {1 \over x}\quad ,x \ne 0} \cr {0 \quad ,x = 0} \cr } } \right.\)在\(x = 0\)处( ). A: 连续且可导 B: 不可导 C: 不连续 D: 连续但不可导

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      下列函数中不是初等函数的是( ). A: \(f(x) = {x^2} + 1\) B: \(f(x) = \tan x\) C: \(f(x) = \arcsin x\) D: \(f(x) = \left\{ \matrix{ {2^x},x \le 0 \ \cr \ln x,x > 0 \ \cr} \right.\)

    • 4

      曲线\( \left\{ {\matrix{ { { x^2} + {y^2} = {z^2}} \cr { { z^2} = y} \cr } } \right. \)在坐标面\( yoz \) 上的投影曲线方程为( ) A: \( \left\{ {\matrix{ { { x^2} + { { \left( {y - {1 \over 2}} \right)}^2} = {1 \over 4}} \cr {z = 0} \cr } } \right. \) B: \( \left\{ {\matrix{ { { z^2} = y} \cr {x = 0} \cr } } \right. \) C: \( \left\{ {\matrix{ {z = {y^2}} \cr {x = 0} \cr } } \right. \) D: \( \left\{ {\matrix{ { { y^2} + { { \left( {x - {1 \over 2}} \right)}^2} = {1 \over 4}} \cr {z = 0} \cr } } \right. \)