• 2022-06-19
    设$f(x)$是连续的奇函数,则定积分$\int_{-1}^1 f(x)dx=$
    A: $2\int_{-1}^0 f(x)dx$
    B: $\int_{-1}^0 f(x)dx$
    C: $\int_{0}^1 f(x)dx$
    D: $0$