设[tex=0.857x1.0]KGogyvwDAIJf/iL0H/9wjg==[/tex]与[tex=0.857x1.286]h9C4nePGcGllh55hxKIsUw==[/tex]相互独立,且[tex=0.857x1.0]KGogyvwDAIJf/iL0H/9wjg==[/tex]在在区间[tex=2.286x1.357]t/28KdVrg5JGYKaENU0GEw==[/tex]上服从均匀分布,且[tex=0.857x1.286]h9C4nePGcGllh55hxKIsUw==[/tex]服从指数分布[tex=1.786x1.357]awqvNHHPYkNPyosONmVKxg==[/tex]则[tex=2.786x1.286]wsm6hZKLwoHLmpiSvjoPLA==[/tex]的联合密度函数为
未知类型:{'options': ['[tex=14.143x3.143]hS/kfu7D0VKWfYWtipKj5TBPm4GOKyZyPQhvECi+FEq2JSkvlksECFgckUSPX6JCoI1hAPwlnyrh1qivp/+lNFI/bHghP5sMYCcIiFpxOqPKxOrvDBoBnQC2erYR/9uj[/tex]', '[tex=13.714x2.429]hS/kfu7D0VKWfYWtipKj5TBPm4GOKyZyPQhvECi+FErMyr2+bpJn1xhgTyrhnz3H03VPrzQmjfy9+kXzRwhrQu3k7bzrtckOA9mikrNFaUs=[/tex]', '[tex=14.214x2.429]hS/kfu7D0VKWfYWtipKj5TBPm4GOKyZyPQhvECi+FEpWIdUi6x6qN7kq9ETqY5+heMbxBCnIDk9DiEx+GfiK+SDL4DORpaGj0B1Snpnf0NI=[/tex]', '[tex=13.357x2.429]hS/kfu7D0VKWfYWtipKj5TBPm4GOKyZyPQhvECi+FEpW+K47dvSHSaTX8CwXXQlBQXUVt/pNlckISVdxt5LQFi7tped8A/3FyRGTK7osSSg=[/tex]'], 'type': 102}
未知类型:{'options': ['[tex=14.143x3.143]hS/kfu7D0VKWfYWtipKj5TBPm4GOKyZyPQhvECi+FEq2JSkvlksECFgckUSPX6JCoI1hAPwlnyrh1qivp/+lNFI/bHghP5sMYCcIiFpxOqPKxOrvDBoBnQC2erYR/9uj[/tex]', '[tex=13.714x2.429]hS/kfu7D0VKWfYWtipKj5TBPm4GOKyZyPQhvECi+FErMyr2+bpJn1xhgTyrhnz3H03VPrzQmjfy9+kXzRwhrQu3k7bzrtckOA9mikrNFaUs=[/tex]', '[tex=14.214x2.429]hS/kfu7D0VKWfYWtipKj5TBPm4GOKyZyPQhvECi+FEpWIdUi6x6qN7kq9ETqY5+heMbxBCnIDk9DiEx+GfiK+SDL4DORpaGj0B1Snpnf0NI=[/tex]', '[tex=13.357x2.429]hS/kfu7D0VKWfYWtipKj5TBPm4GOKyZyPQhvECi+FEpW+K47dvSHSaTX8CwXXQlBQXUVt/pNlckISVdxt5LQFi7tped8A/3FyRGTK7osSSg=[/tex]'], 'type': 102}
举一反三
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为? A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 设随机变量 [tex=0.857x1.0]KGogyvwDAIJf/iL0H/9wjg==[/tex] 与 [tex=0.643x1.0]jDVSpgNhHe+VJmgvx3gg1Q==[/tex] 相互独立,且服从参数为 1 的指数分布. 记 [tex=13.5x1.357]ZrmgIX329+lIMwj+0JP7oX4KmceUiv4NOTdLGvSfjGFY26aIR9qNFK9EJaP3gu/x[/tex] 求[tex=3.857x1.357]t0PsS3YAPSnhTBV9LUFwGQ==[/tex]
- 已知随机变量[tex=0.857x1.0]KGogyvwDAIJf/iL0H/9wjg==[/tex]服从参数为[tex=0.643x1.0]L2Atb4d5eWga5JCvxFtwvQ==[/tex]的泊松分布,[tex=4.857x1.357]F4m+q5YLqz1CpMYzT+XifA==[/tex], 则[tex=2.429x1.357]mcPoV0l2+P69G4jqQuIxgA==[/tex] A: 3 B: 1 C: 2 D: 0