举一反三
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为? A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 如果[tex=4.357x1.0]VanW/03J2cv35k1k0hvblQ==[/tex],矩阵[tex=0.786x1.0]ri6gmnf1+J9dGqG5/1sV6A==[/tex]就称为[tex=0.786x1.0]Yn3GgEZev6SOu2r4v1WnCw==[/tex]与可交换,设[tex=6.571x2.786]sSXBpxJWudVpH1R35o4LnAVLBQ/LjQTM9mCDWHIfd8X0WxsDxscdAR0/v5zAZc5DdJ8TCBQRvjSWiU4ntpEf3w==[/tex]求所有与 [tex=0.786x1.0]Yn3GgEZev6SOu2r4v1WnCw==[/tex]可交换的矩阵.
- 设三阶对称矩阵[tex=0.786x1.0]Yn3GgEZev6SOu2r4v1WnCw==[/tex]的特征值为6,3,3,与特征值6对应的特征向量为[tex=5.286x1.5]7SO+1xanaUBExj3X4I1Ptj6zjgGXxaG/QZ3ARAaDg0U=[/tex],求[tex=0.786x1.0]Yn3GgEZev6SOu2r4v1WnCw==[/tex] .
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- set1 = {x for x in range(10) if x%2==0} print(set1) 以上代码的运行结果为? A: {0, 2, 4, 6} B: {2, 4, 6, 8} C: {0, 2, 4, 6, 8} D: {4, 6, 8}
内容
- 0
假设“☆”是一种新的运算,若3☆2=3×4,6☆3=6×7×8,x☆4=840(x>0),那么x等于: A: 2 B: 3 C: 4 D: 5 E: 6 F: 7 G: 8 H: 9
- 1
如果[tex=3.857x1.0]WEeqNxLhaKfDAau4UVxvjg==[/tex] ,矩阵[tex=0.786x1.0]ri6gmnf1+J9dGqG5/1sV6A==[/tex]就称为与[tex=0.786x1.0]Yn3GgEZev6SOu2r4v1WnCw==[/tex]可交换,设[tex=29.643x3.5]sB265b1+2I6W6CJtJWrQ0DNdWoL8Nc/dR9sqqvwbt8fxo1CTqALOC9IFUHx1zHLI3m5jzt9+vGnn1DM+MEd7/wAKoOhSgM/qq+t8728zMk0+9gSllESX8t8f9GfXDT+gNTqxUdtOG6VK2xvHiXXyHGcVX4aHrIWm4ZCU1h03jmEGko9v0cgihxCaQGpl0TinN+fbMgp+Wz+zuveZcpjm4huckIh41SDCX78btvMM7tjLac/ZyUS/3JQgqajENpLXQqPfDAydZh28RLV9pt5jA9biXts3fU9XgoiTHHYFSjK/ZDPmhg/y5i2cSAzKWa1ZSUqKgFMYTNoM3AWGLcOMmUgQGDXT9muctPW7Mdq2xwEwEtEMVsqIWQCJH/obNJZneDJ1EgYZxBD2b7VIeOtJyQ==[/tex]求所有与[tex=0.786x1.0]Yn3GgEZev6SOu2r4v1WnCw==[/tex]可交换的矩阵.
- 2
用某种方法排序,调整序列如下,所选排序方法为( )。7 4 2 8 1 0 6 30 4 2 8 1 7 6 30 1 2 8 4 7 6 30 1 2 8 4 7 6 30 1 2 3 4 7 6 80 1 2 3 4 7 6 80 1 2 3 4 6 7 80 1 2 3 4 6 7 8
- 3
令[tex=5.929x2.786]YHIKtHtTy6YeetIBukGWJ29FyEYWVBSkIYhOTWWwEFNeu6iwkaZUSw0MxAVdDIZja+GqhBOYN7rzj76h8n0OTAQxZ8CYMcIQ6P/H2SSArFo=[/tex]找出计算[tex=1.357x1.071]317mMb/UfJBjZHDU7raSnoMld3At9ac3IkG0+iYzd/8=[/tex]的公式,其中[tex=0.643x0.786]SBMIs+VUk7//BOpfqlQl0w==[/tex]为正整数。
- 4
【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=