Calculate the low frequency break point due to the capacitor CS for this BJT amplifier. [img=401x275]1803966add25148.png[/img]
A: fLs = [img=98x43]1803966ae83ee52.png[/img] = 280.25 Hz
B: fLs =[img=130x43]1803966af50fda0.png[/img] = 30.6 Hz
C: fLs = [img=96x43]1803966aff1bc04.png[/img] = 5585.4 Hz.
D: fLs = [img=132x43]1803966b0d87e79.png[/img] = 4.269 Hz.
A: fLs = [img=98x43]1803966ae83ee52.png[/img] = 280.25 Hz
B: fLs =[img=130x43]1803966af50fda0.png[/img] = 30.6 Hz
C: fLs = [img=96x43]1803966aff1bc04.png[/img] = 5585.4 Hz.
D: fLs = [img=132x43]1803966b0d87e79.png[/img] = 4.269 Hz.
举一反三
- 调频信号[img=306x27]180301dd083b62d.png[/img]的带宽为 。 A: [img=79x24]180301dd1090b23.png[/img]Hz B: [img=79x24]180301dd18a918d.png[/img]Hz C: [img=79x24]180301dd20e87fe.png[/img]Hz D: [img=56x24]180301dd29b79b3.png[/img]Hz
- 调频信号[img=306x27]1802d4efbe21c95.png[/img]的带宽为 。 A: [img=79x24]1802d4efc5f1505.png[/img]Hz B: [img=79x24]1802d4efcef9f70.png[/img]Hz C: [img=79x24]1802d4efd70a5fe.png[/img]Hz D: [img=56x24]1802d4efdfae6b9.png[/img]Hz
- 下列4个集合中是空集的是（） A: ｛x|[img=18x22]1802f060e2f728f.png[/img]+1=0｝ B: ｛x|[img=18x22]1802f060e2f728f.png[/img]<-x｝ C: ｛x|[img=18x22]1802f060e2f728f.png[/img]=0｝ D: ｛x|[img=18x22]1802f060e2f728f.png[/img]-1=0｝
- 下列4个集合中是空集的是（） A: ｛x|[img=18x22]1803d021d498831.png[/img]+1=0｝ B: ｛x|[img=18x22]1803d021d498831.png[/img]<-x｝ C: ｛x|[img=18x22]1803d021d498831.png[/img]=0｝ D: ｛x|[img=18x22]1803d021d498831.png[/img]-1=0｝
- 下列4个集合中是空集的是（） A: ｛x|[img=18x22]1803d0240bcad39.png[/img]+1=0｝ B: ｛x|[img=18x22]1803d0240bcad39.png[/img]-x｝ C: ｛x|[img=18x22]1803d0240bcad39.png[/img]=0｝ D: ｛x|[img=18x22]1803d0240bcad39.png[/img]-1=0｝