• 2022-06-07 问题

    Calculate the low frequency break point due to the capacitor CS for this BJT amplifier. [img=401x275]1803966add25148.png[/img] A: fLs = [img=98x43]1803966ae83ee52.png[/img] = 280.25 Hz B: fLs =[img=130x43]1803966af50fda0.png[/img] = 30.6 Hz C: fLs = [img=96x43]1803966aff1bc04.png[/img] = 5585.4 Hz. D: fLs = [img=132x43]1803966b0d87e79.png[/img] = 4.269 Hz.

    Calculate the low frequency break point due to the capacitor CS for this BJT amplifier. [img=401x275]1803966add25148.png[/img] A: fLs = [img=98x43]1803966ae83ee52.png[/img] = 280.25 Hz B: fLs =[img=130x43]1803966af50fda0.png[/img] = 30.6 Hz C: fLs = [img=96x43]1803966aff1bc04.png[/img] = 5585.4 Hz. D: fLs = [img=132x43]1803966b0d87e79.png[/img] = 4.269 Hz.

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