continue;System.out.print(x+” ”);}
A: 1 2 3
B: 3 4
C: 1 2
D: 2 3 4
A: 1 2 3
B: 3 4
C: 1 2
D: 2 3 4
举一反三
- 方程${{x}^{2}}{{y}^{''}}-(x+2)(x{{y}^{'}}-y)={{x}^{4}}$的通解是( ) A: $y={{C}_{1}}x+{{C}_{2}}{{e}^{x}}-(\frac{1}{2}{{x}^{3}}+{{x}^{2}})$ B: $y={{C}_{1}}x+{{C}_{2}}{{e}^{x}}-(\frac{1}{2}{{x}^{3}}+{{x}^{4}})$ C: $y={{C}_{1}}x+{{C}_{2}}x{{e}^{x}}-(\frac{1}{2}{{x}^{3}}+{{x}^{4}})$ D: $y={{C}_{1}}x+{{C}_{2}}x{{e}^{x}}-(\frac{1}{2}{{x}^{3}}+{{x}^{2}})$
- 阅读下面Python代码，选择正确输出结果：（） for i in range(5): if i == 3: continue print(i,end=" ") continue print(i,end=" ") A: 0 1 2 3 4 5 B: 0 1 2 3 4 C: 2000 1 2 D: 0 1 2 4
- a = [x for x in range(4) if x % 2 ==1]，语句print(a)输出为 A: [1, 2, 3] B: [0, 1, 2, 3] C: [0, 2] D: [1, 3]
- for i in range(4,1,-1): print(i,end=" ") 上述程序的输出结果是： A: 4 3 2 1 B: 4 3 2 C: 1 2 3 4 D: 1 2 3
- count=5while(count>1): print(count,end="") count-=1输出是什么 A: 1 2 3 4 5 B: 2 3 4 5 C: 5 4 3 2 1 D: 5 4 3 2