• 2022-06-07
    控制系统的框图如图所示。已知[tex=6.286x1.357]nMt0EUSBw6o4b65Z7U59gw==[/tex],求系统总的稳态误差。[img=418x93]1794b8966fa9f7c.png[/img]
  • 求[tex=1.5x1.0]NPQ/li6T5OSm81duTFJ2NQ==[/tex],令[tex=3.0x1.357]CstScC1MveCU6UNR9TnRvA==[/tex]系统开环传递函数为[tex=12.429x2.714]2XBsv7YRn5vyTDV1lOtWPm/t6Ld84mJxF9V0czzlD9omMSq8aOk15g8wHtY/Z6ngiZMcpfxKsXOuZTfwsa19HDzXzQDndxHGhdYtCRiIZGA=[/tex]由静态误差系数法得[tex=12.0x4.929]Ck4j1YFlvVH5wCAykOEMixRNMQ7MeeDG99dxZUQo6RKBbfoROq/f6p3+3xa1zi2zJsb26QRszjO2oglbUH+bpRiMv4zYhLPcV8uBT1ldzBgwxWlRYngWc7Sd3M7Z9sOAah2j+MXAgpkBc7ytcuBoQf6GN458Cq3ppaLxYKcZGBN98xGYEhFzNg6BWprq0wiI[/tex]求[tex=1.5x1.0]MbEzQZ6VFlY0KMuEWBEWug==[/tex],令[tex=2.929x1.357]QX2JlV+yR61IepHeobhbvQ==[/tex]由终值定理得[tex=21.571x3.0]da2F3+ZaDoTu7d/bgSSJeJlmjarL9DSkuHUugs+b5XpXBLiiTYa3hORR3BH9Posf2azi/HKhoEaL/SuzK/T+/czY/CLcJU9piGdvcRBtNMi9q0soVQrMAvmFMgbAd6GMhwbiZM+mXQGbqGA/j9H/dZ82fHTlNrtcSdKGxJES0JXyXV0WfjDr01L4TvkiPgeD[/tex]所以,系统总的稳态误差为[tex=10.5x2.571]DjEu5WjyR+8BWqn0d0UQTBqrZN/Ber2Vhm/tp04hKbeqmM//NmogVyHbHg30chdHEJSYhZjYZVYcZ/K3HRsvUA==[/tex]

    内容

    • 0

      试求如图2-8-1(c)所示系统的输出z变换[tex=2.0x1.357]XE+SDQSY28NTqzYsjeii4w==[/tex].[img=448x168]179744d767d1b82.png[/img]

    • 1

      试求如图2-8-1(d)所示系统的输出z变换[tex=2.0x1.357]XE+SDQSY28NTqzYsjeii4w==[/tex].[img=540x206]17979bb69703b5c.png[/img]

    • 2

      试求如图2-8-1(e)所示系统的输出z变换[tex=2.0x1.357]XE+SDQSY28NTqzYsjeii4w==[/tex].[img=534x192]1797456ed942b1e.png[/img]

    • 3

      一系统的框图如图[tex=2.5x1.286]8FqpIWgejyA1K+M08JrX5A==[/tex]所示,试求该系统的单位取样响应[tex=1.857x1.286]WQOYJimkWLPqh3ayghahYA==[/tex]和单位阶跃响应[img=536x227]17d36ae58e32339.png[/img]

    • 4

      系统结构图如图( a) 所示,其单位阶跃响应为[tex=1.571x1.357]Ozfnfn0aEim+LTokvhO4nw==[/tex], 如图[tex=1.357x1.357]jV8pqpEsW+eMvrqtcb9HhA==[/tex] 所示,系统的稳态 位置误差 [tex=2.429x1.214]cpam6jP6OLITsLUmSNkn2g==[/tex] 。试确定 [tex=4.071x1.286]q5RRbh4cVaYQIQhbelXZLzXlirNVc3IaXnyeGvp5H8E=[/tex]值。[br][/br][img=753x318]17a575a585a5dd8.png[/img]