设 [tex=0.857x1.286]ZpwhzmyivskaH5M1X7ozaQ==[/tex] 为 [tex=0.786x1.286]dSWbQCTjdbLxKy7q0ps2gg==[/tex] 上 [tex=0.643x0.786]/he/ol8BkDuTTL9yMPtH4Q==[/tex] 维线性空间. [tex=4.5x1.071]d9y+KLOQpwgiIZSOmy+NwuKjcx8pDZqu3h/Q7GEiRUWsitTO5mMLH8wF4N4pZRWx[/tex] [tex=1.0x1.0]XyzqB7VduQKuYOSYbtY4TQ==[/tex] 为 [tex=0.857x1.286]ZpwhzmyivskaH5M1X7ozaQ==[/tex] 的子空间. [tex=9.143x1.357]N9dOzoEP62XohFERsEMpa2KyZcTDUOKkxV5al4c4zXfioI+38ZHntN3Pf7e2CD2sm8trZqWKDvESKlRpunPzeQ==[/tex] 证明 [tex=15.857x1.357]NovbxKl63Ey/milqTcbe/77BIJFM7Bwv6Jpu9w6yQOABriEkIESbhU5mAczCl7oMD+WEWFyQOwQdyq+Z1W8FB4lvgYHEQQPEhMmak8OGud90OalRo/QhPADZxVhN2wEObF+/N1LAVZ4Vhj8aQCAc5m7mMHeHlS1rpzgJSni4Asw=[/tex]证 $\quad$ 因为 $\mathcal{A}$ 限制在 $W$ 上是 $W$ 到 $\mathcal{A}(W)$ 的线性映射，而此限制的核为 $\operatorname{ker} \mathcal{A} \cap$ $W$，于是 $\operatorname{dim} \mathcal{A}(W)+\operatorname{dim}(\operatorname{ker} \mathcal{A} \cap W)=\operatorname{dim} W$..[br][/br]
举一反三
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 下列数组声明语句中，不正确的是_________。 A: Dim a(9) As Single = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} B: Dim a() = {1, 2, 3, 4, 5, 6, 10} C: Dim a( ,) As Single = {{1, 2, 3, 4, 5}, {6, 7, 8, 9, 10}} D: Dim a() As Single = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} E: Dim n As Integer=10Dim a(n) As Single
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 输出九九乘法表。 1 2 3 4 5 6 7 8 9 --------------------------------------------------------------------- 1*1=1 2*1=2 2*2=4 3*1=3 3*2=6 3*3=9 4*1=4 4*2=8 4*3=12 4*4=16 5*1=5 5*2=10 5*3=15 5*4=20 5*5=25 6*1=6 6*2=12 6*3=18 6*4=24 6*5=30 6*6=36 7*1=7 7*2=14 7*3=21 7*4=28 7*5=35 7*6=42 7*7=49 8*1=8 8*2=16 8*3=24 8*4=32 8*5=40 8*6=48 8*7=56 8*8=64 9*1=9 9*2=18 9*3=27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=81
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']