(接上题)(2)设经分界面反射的波的振幅和入射波的振幅相等,则反射波的波函数是 A: $y_{r}=Acos \left(2\pi \nu t+\dfrac{2\pi\nu}{u}x-\dfrac{\pi}{2} \right),0\le x\le\dfrac{3\lambda}{4}$ B: $y_{r}=Acos \left(2\pi \nu t+\dfrac{2\pi\nu}{u}x \right),0\le x\le\dfrac{3\lambda}{4}$ C: $y_{r}=Acos \left(2\pi \nu t+\dfrac{2\pi\nu}{u}x-\dfrac{\pi}{4} \right),0\le x\le\dfrac{3\lambda}{4}$ D: $y_{r}=Acos\left(2\pi \nu t-\dfrac{2\pi\nu}{u}x \right),0\le x\le\dfrac{3\lambda}{4}$
(接上题)(2)设经分界面反射的波的振幅和入射波的振幅相等,则反射波的波函数是 A: $y_{r}=Acos \left(2\pi \nu t+\dfrac{2\pi\nu}{u}x-\dfrac{\pi}{2} \right),0\le x\le\dfrac{3\lambda}{4}$ B: $y_{r}=Acos \left(2\pi \nu t+\dfrac{2\pi\nu}{u}x \right),0\le x\le\dfrac{3\lambda}{4}$ C: $y_{r}=Acos \left(2\pi \nu t+\dfrac{2\pi\nu}{u}x-\dfrac{\pi}{4} \right),0\le x\le\dfrac{3\lambda}{4}$ D: $y_{r}=Acos\left(2\pi \nu t-\dfrac{2\pi\nu}{u}x \right),0\le x\le\dfrac{3\lambda}{4}$
(2)设经分界面反射的波的振幅和入射波的振幅相等,则反射波的波函数是 A: $y_{r}=Acos \left(2\pi \nu t+\dfrac{2\pi\nu}{u}x-\dfrac{\pi}{2} \right),0\le x\le\dfrac{3\lambda}{4}$ B: $y_{r}=Acos \left(2\pi \nu t+\dfrac{2\pi\nu}{u}x \right),0\le x\le\dfrac{3\lambda}{4}$ C: $y_{r}=Acos \left(2\pi \nu t+\dfrac{2\pi\nu}{u}x-\dfrac{\pi}{4} \right),0\le x\le\dfrac{3\lambda}{4}$ D: $y_{r}=Acos\left(2\pi \nu t-\dfrac{2\pi\nu}{u}x \right),0\le x\le\dfrac{3\lambda}{4}$
(2)设经分界面反射的波的振幅和入射波的振幅相等,则反射波的波函数是 A: $y_{r}=Acos \left(2\pi \nu t+\dfrac{2\pi\nu}{u}x-\dfrac{\pi}{2} \right),0\le x\le\dfrac{3\lambda}{4}$ B: $y_{r}=Acos \left(2\pi \nu t+\dfrac{2\pi\nu}{u}x \right),0\le x\le\dfrac{3\lambda}{4}$ C: $y_{r}=Acos \left(2\pi \nu t+\dfrac{2\pi\nu}{u}x-\dfrac{\pi}{4} \right),0\le x\le\dfrac{3\lambda}{4}$ D: $y_{r}=Acos\left(2\pi \nu t-\dfrac{2\pi\nu}{u}x \right),0\le x\le\dfrac{3\lambda}{4}$
下列程序运行后,看到的图形( ?????)。 ?????t=0:pi/6:2*pi;[x,y,z]=cylinder(t, 6);surf(x,y,z)view(0,90);axis equal
下列程序运行后,看到的图形( ?????)。 ?????t=0:pi/6:2*pi;[x,y,z]=cylinder(t, 6);surf(x,y,z)view(0,90);axis equal
下列程序运行后,看到的图形()。t=0:pi/6:2*pi;[x,y,z]=...ew(0,90);axis equal
下列程序运行后,看到的图形()。t=0:pi/6:2*pi;[x,y,z]=...ew(0,90);axis equal
使用语句( )可以建立[0,pi]之间的等差数组。? x=linspace(0,pi,6)|x=0:pi/5:pi|x=0:pi:0.1|x=linspace(0,6,pi)
使用语句( )可以建立[0,pi]之间的等差数组。? x=linspace(0,pi,6)|x=0:pi/5:pi|x=0:pi:0.1|x=linspace(0,6,pi)
函数$f(x)=\sin x + \cos x,x \in [0,2 \pi]$的上凸区间为 A: $[0,\frac{\pi}{4}] \cup [\frac{5}{4} \pi,2 \pi] $ B: $[\frac{\pi}{4},\frac{5}{4} \pi]$ C: $[0,\frac{3}{4}\pi] \cup [\frac{7}{4} \pi,2 \pi] $ D: $[\frac{3}{4} \pi,\frac{7}{4} \pi] $
函数$f(x)=\sin x + \cos x,x \in [0,2 \pi]$的上凸区间为 A: $[0,\frac{\pi}{4}] \cup [\frac{5}{4} \pi,2 \pi] $ B: $[\frac{\pi}{4},\frac{5}{4} \pi]$ C: $[0,\frac{3}{4}\pi] \cup [\frac{7}{4} \pi,2 \pi] $ D: $[\frac{3}{4} \pi,\frac{7}{4} \pi] $
8. 下列不等式正确的是 A: $0\lt \int_{0}^{\frac{\pi }{2}}{\sin (\sin x)dx}\lt \int_{0}^{\frac{\pi }{2}}{\cos (\sin x)dx}$ B: $0\lt \int_{0}^{\frac{\pi }{2}}{\cos (\sin x)dx}\lt \int_{0}^{\frac{\pi }{2}}{\sin (\sin x)dx}$ C: $\int_{0}^{\frac{\pi }{2}}{\sin (\sin x)dx}\lt 0\lt \int_{0}^{\frac{\pi }{2}}{\cos (\sin x)dx}$ D: $\int_{0}^{\frac{\pi }{2}}{\cos (\sin x)dx}\lt 0\lt \int_{0}^{\frac{\pi }{2}}{\sin (\sin x)dx}$
8. 下列不等式正确的是 A: $0\lt \int_{0}^{\frac{\pi }{2}}{\sin (\sin x)dx}\lt \int_{0}^{\frac{\pi }{2}}{\cos (\sin x)dx}$ B: $0\lt \int_{0}^{\frac{\pi }{2}}{\cos (\sin x)dx}\lt \int_{0}^{\frac{\pi }{2}}{\sin (\sin x)dx}$ C: $\int_{0}^{\frac{\pi }{2}}{\sin (\sin x)dx}\lt 0\lt \int_{0}^{\frac{\pi }{2}}{\cos (\sin x)dx}$ D: $\int_{0}^{\frac{\pi }{2}}{\cos (\sin x)dx}\lt 0\lt \int_{0}^{\frac{\pi }{2}}{\sin (\sin x)dx}$
set1 = {x for x in range(10) if x%2==0} print(set1) 以上代码的运行结果为? A: {0, 2, 4, 6} B: {2, 4, 6, 8} C: {0, 2, 4, 6, 8} D: {4, 6, 8}
set1 = {x for x in range(10) if x%2==0} print(set1) 以上代码的运行结果为? A: {0, 2, 4, 6} B: {2, 4, 6, 8} C: {0, 2, 4, 6, 8} D: {4, 6, 8}
x属于(0,pi/2),sinx/x≥2/pi
x属于(0,pi/2),sinx/x≥2/pi
如上图所示实例,以下测试用例哪一组不能够满足判定覆盖________。 A: (a=2,b=0,x=6)、(a=1,b=0,x=1) B: (a=2,b=0,x=4)、(a=3,b=0,x=2) C: (a=2,b=2,x=2)、(a=3,b=0,x=6) D: (a=2,b=0,x=6)、(a=2,b=0,x=4)
如上图所示实例,以下测试用例哪一组不能够满足判定覆盖________。 A: (a=2,b=0,x=6)、(a=1,b=0,x=1) B: (a=2,b=0,x=4)、(a=3,b=0,x=2) C: (a=2,b=2,x=2)、(a=3,b=0,x=6) D: (a=2,b=0,x=6)、(a=2,b=0,x=4)