设数列[tex=2.0x1.286]LAoOkQ1vinSKecEUCB/5UA==[/tex]的前[tex=0.643x1.286]ZsZs11iKEvfmzDIurZth8g==[/tex]项和为[tex=1.071x1.286]prwe1BcWngzznU+UlTPxnw==[/tex]，则[tex=2.0x1.286]LAoOkQ1vinSKecEUCB/5UA==[/tex]为等差数列。（1）[tex=5.714x1.286]CgaOUevEdfcG81SxZYeP5g==[/tex]，[tex=4.214x1.286]RW6jIba+BoBFGr+9wltYLw==[/tex]；（2）[tex=7.357x1.286]sAyFOuyA7lujAbGaVE2K3gUMXKLuQYzLvlHYFX9qubQ=[/tex]，[tex=4.214x1.286]RW6jIba+BoBFGr+9wltYLw==[/tex]。 A: 条件（1）充分，但条件（2）不充分. B: 条件（2）充分，但条件（1）不充分. C: 条件（1）和（2）单独都不充分，但条件（1）和条件（2）联合起来充分. D: 条件（1）充分，条件（2）也充分. E: 条件（1）和条件（2）单独都不充分，条件（1）和条件（2）联合起来也不充分.

等比数列[tex=2.0x1.286]LAoOkQ1vinSKecEUCB/5UA==[/tex]中，[tex=2.857x1.286]cu7Ar8T1w9T9NG7n8Twcow==[/tex]，[tex=3.286x1.286]1PTM4QcMKpYxSMxcEc97oA==[/tex]，则[tex=1.071x1.286]bpgROLEtok4K7dloAOyokA==[/tex]可为 A: 28 B: 32 C: -21 D: -21或28 E: 35

“对任意给定的[tex=3.786x1.286]c1/og1aspHSJ4BEtDD+3dXy222gUDPhlcUi61pTs1MU=[/tex]，总存在正整数[tex=0.929x1.286]9yLabwWeyn0cMD+fIBc3Rg==[/tex]，当[tex=2.786x1.286]ZJ9yJ5d5NetjEKDQPoH925GBi072Ep8G4Vzw8NRZOGg=[/tex]时，恒有[tex=5.571x1.286]gVC509fwZrFkzBSmdjkGXiO4sxGboFxvt1HACmsO9uPh8W/ZCU6Ema5VuNvR2ZKf[/tex]”是数列[tex=2.0x1.286]LAoOkQ1vinSKecEUCB/5UA==[/tex]收敛于[tex=0.571x1.286]mRKL/orzOudCEARA8qn3Kw==[/tex]的 A: 充分条件但非必要条件 B: 必要条件但非充分条件 C: 充分必要条件 D: 既非充分条件又非必要条件

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是（）。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

请仔细观察下面行列式的计算过程，如果四个等号都理解了，请选择A，否则请选择B。 | a 1 1 1 1 | |a＋4 a＋4 a＋4 a＋4 a＋4| | 1 a 1 1 1 | | 1 a 1 1 1 | | 1 1 a 1 1 |= | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 a | | 1 1 1 1 1 | | 1 a 1 1 1 | =(a＋4) | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 1 | | 0 a–1 0 0 0 | =(a＋4) | 0 0 a–1 0 0 | | 0 0 0 a–1 0 | | 0 0 0 0 a–1 | =(a＋4)(a–1)^4

共有4个站进行码分多址通信。4个站的码片序列为：a：（-1 -1 -1 +1 +1 -1 +1 +1） b：（-1 -1 +1 -1 +1 +1 +1 -1） c：（-1 +1 -1 +1 +1 +1 -1 -1） d：（-1 +1 -1 -1 -1 -1 +1 -1） 现收到这样的码片序列：（-1 +1 -3 +1 -1 -3 +1 +1），则（ ）发送1。

共有四个站进行CDMA通信，现收到这样的码片序列（-3 +1 -1 -1 +1 +1 +1 -3），则下列站点发送了数据1的是（ ） A: （-1 -1 -1 +1 +1 -1 +1 +1） B: （-1 -1 +1 -1 +1 +1 +1 -1） C: （-1 +1 -1 +1 +1 +1 -1 -1） D: （-1 +1 -1 -1 -1 -1 +1 -1）