若输入52，则下面程序的运行结果是 。 main() {int a[8]={6,12,18,42,46,52,67,73}; int low=0,mid,high=7,x; printf("Input a x:"); scanf("%d",&x); while(low<=high) {mid=(low+high)/2; if(x>a[mid]) low=mid+1; else if(x Search Successful! The index is:5

若输入52<;CR>;，则下面程序的运行结果是。main(){int a&#91;8&#93;={6,12,18,42,46,52,67,73};int low=0,mid,high=7,x;printf("Input a x:");scanf("%d",&amp;x);while(low<;=high){mid=(low+high)/2;if(x>;a&#91;mid&#93;) low=mid+1;else if(x<;a&#91;mid&#93;) high=mid-1;else break;}if(low<;=high) printf("Search Successful! The index is:%d\n",mid);else printf("Can't search!\n");}

The aphotic zone (bottom of the ocean) will have ____ and ____ while the photic zone (surface of the ocean) will have ____ and ____. A: low temperature, low salinity; high temperature, high salinity B: low temperature, high salinity; high temperature, low salinity C: high temperature, high salinity; low temperature, low salinity D: high temperature, low salinity; low temperature, high salinity E: both have equal temperature and salinity

ENUM类型的字段level定义为（LOW、MIDDLE、HIGH），ORDER BY level asc的顺序是 A: HIGH、LOW、MIDDLE B: LOW、MIDDLE、HIGH C: MIDDLE、LOW、HIGH D: HIGH、MIDDLE、LOW

Air tends to flow from a _______ pressure area to a _______ pressure. A: high, lower B: low, higher C: high, high D: low, low

The high level and low level specified by LVTTL are ________. A: high level 5.0V low level 0V B: high level 3.3V low level 0V C: high level 2.4V~5.0V low level 0V~0.5V D: high level 2.4V~3.3V low level 0V~0.4V

黄璐同学在示范课中所展示的音域为？ A: low C～high c B: low E～high c C: low C~high e D: low D～high c

Due to its impulse to pursue high profits, international hot money is bound to look for which of the following investment fields? A: Low risk, low profit B: Low risk, high profit C: High risk, high profit D: High risk, low profit

假设待查找区间的起始位置和终止位置分别为low和high，则二分查找算法在下面情况出现时说明找不到要查找的数据（ ）。 A: low >high B: low<high C: low=high D: low<=high

折半查找，完善以下程序： #include main() { int a[10]={1,3,5,7,9,11,13,15,17,19},k,low,high,mid,cnt; low=0;high=9;cnt=0; printf("请输入要查找的数："); scanf("%d",&k); while( 空1 ) { cnt++; mid=(low+high)/2; if(k == a[mid]) break; else if(k > a[mid]) 空2 空3 }