【单选题】"2019年武汉市确诊新型冠状病毒nCoV肺炎流行病学特征分析"的核心概念是 A. 武汉市 B. 新型冠状病毒nCoV肺炎 C. 新型冠状病毒nCoV D. 流行病学

世界卫生组织对新型冠状病毒的命名为( ) A: SARS-CoV B: 2020-nCoV C: 2019-nCoV D: SARI

世界卫生组织(WHO)将新型冠状病毒命名为 A: 2020-nCov B: 2019-nCov C: SARS-CoV D: MERS-CoV

新型冠状病毒肺炎英文缩写为（）。 A: SARS B: MERS C: NCP D: NCOV E: H7N9

下面代码的执行结果是： ls = [“2020”, “2020”, “Python”] ls.append(2020) ls.append([2020, “2020”]) print(ls): [‘2020’, ‘2020’, ‘Python’, 2020, 2020, ‘2020’]|[‘2020’, ‘2020’, ‘Python’, 2020, [2020, ‘2020’]]|[‘2020’, ‘2020’, ‘Python’, 2020, [‘2020’]]|[‘2020’, ‘2020’, ‘Python’, 2020]

下面代码的执行结果是‪‬‪‬‪‬‪‬‪‬‮‬‫‬‭‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‪‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‪‬‪‬( )‪‬‪‬‪‬‪‬‪‬‮‬‫‬‭‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‪‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‪‬‪‬ ‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬‬。ls = ["2020", "20.20", "Python"] ls.append(2020)ls.append([2020, "2020"])print(ls) A: ['2020', '20.20', 'Python', 2020, 2020, '2020'] B: ['2020', '20.20', 'Python', 2020, [2020, '2020']] C: ['2020', '20.20', 'Python', 2020] D: ['2020', '20.20', 'Python', 2020, ['2020']]

下面代码的执行结果是：‪‪‪‪‪‪‫‪‪‪‪‪‪‫‪‪‪‪‪‫‪‪‪‪‪‫‪‪‪‪‪‪‫‪‪‪‪‪‪‫ ls = ["2020", "20.20", "Python"] ls.append(2020) ls.append([2020, "2020"]) print(ls) A: ['2020', '20.20', 'Python', 2020, ['2020']] B: ['2020', '20.20', 'Python', 2020, 2020, '2020'] C: ['2020', '20.20', 'Python', 2020] D: ['2020', '20.20', 'Python', 2020, [2020, '2020']]

以下代码的输出结果是______。ls = ["2020", "20.20", "Python"]ls.append(2020)ls.append([2020, "2020"])print(ls) A: ['2020', '20.20', 'Python', 2020] B: ['2020', '20.20', 'Python', 2020, [2020, '2020']] C: ['2020', '20.20', 'Python', 2020, 2020, '2020'] D: ['2020', '20.20', 'Python', 2020, ['2020']]

下面代码的执行结果是：（ ）ls= [“2020”, “20.20”, “Python”]ls.append(2020)ls.append([2020, “2020”])print(ls) A: [‘2020’, ‘20.20’, ‘Python’, 2020] B: [‘2020’, ‘20.20’, ‘Python’, 2020, [2020, ‘2020’]] C: [‘2020’, ‘20.20’, ‘Python’, 2020, [‘2020’]] D: [‘2020’, ‘20.20’, ‘Python’, 2020, 2020, ‘2020’]r

以下代码的输出结果是( )。 ls = ["2020", "20.20", "Python"] ls.append([2020, "2020"]) [br][/br]print(ls) A: ['2020', '20.20', 'Python', [2020, '2020']] B: ['2020', '20.20', 'Python', 2020, ['2020']] C: ['2020', '20.20', 'Python', 2020,] D: ['2020', '20.20', 'Python', 2020, '2020']