• 2022-06-12 问题

    qia错g支弹药有制式和非制式之分()

    qia错g支弹药有制式和非制式之分()

  • 2022-11-01 问题

    一个“吃”字,在上古音读,中古音读,现代音分别读作() A: qia B: ka C: qi D: chi

    一个“吃”字,在上古音读,中古音读,现代音分别读作() A: qia B: ka C: qi D: chi

  • 2022-06-04 问题

    设随机变量[tex=2.786x1.286]AG5D6gU/evQZlfwisXgzYw==[/tex]的分布律为[img=638x158]177b451254d5293.png[/img]求[tex=5.214x1.286]PoKwVBvteZfTliyaHi1QiA==[/tex]的分布律 .

    设随机变量[tex=2.786x1.286]AG5D6gU/evQZlfwisXgzYw==[/tex]的分布律为[img=638x158]177b451254d5293.png[/img]求[tex=5.214x1.286]PoKwVBvteZfTliyaHi1QiA==[/tex]的分布律 .

  • 2022-06-04 问题

    设随机变量 [tex=2.786x1.286]wsm6hZKLwoHLmpiSvjoPLA==[/tex] 的分布律为[p=align:center][img=741x245]1776ac94830978d.png[/img]求 [tex=5.214x1.286]PoKwVBvteZfTliyaHi1QiA==[/tex] 的分布律

    设随机变量 [tex=2.786x1.286]wsm6hZKLwoHLmpiSvjoPLA==[/tex] 的分布律为[p=align:center][img=741x245]1776ac94830978d.png[/img]求 [tex=5.214x1.286]PoKwVBvteZfTliyaHi1QiA==[/tex] 的分布律

  • 2022-11-02 问题

    中国古代建筑的木构件之间主要是采用()的方式进行连接。 A: 榫卯 B: 夯筑 C: 卡(qia)接 D: 砂浆砌筑

    中国古代建筑的木构件之间主要是采用()的方式进行连接。 A: 榫卯 B: 夯筑 C: 卡(qia)接 D: 砂浆砌筑

  • 2022-06-03 问题

    在病人的知情同一种有代理人同意,也称亲属同意。代理人同意有相应的条件,但代理人同意的前提应该是 ( ) A: 以亲属的最大利益为前提 B: 以医生的最大利益为qia C: 以护理人员的最大利益为前提 D: 以病人的最大利益为前提

    在病人的知情同一种有代理人同意,也称亲属同意。代理人同意有相应的条件,但代理人同意的前提应该是 ( ) A: 以亲属的最大利益为前提 B: 以医生的最大利益为qia C: 以护理人员的最大利益为前提 D: 以病人的最大利益为前提

  • 2022-06-01 问题

    for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是:__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

    for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是:__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

  • 2021-04-14 问题

    【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

    【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

  • 2022-06-01 问题

    for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是()。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

    for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是()。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

  • 2022-10-25 问题

    下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

    下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

  • 1 2 3 4 5 6 7 8 9 10