• 2022-06-06 问题

    在窗体上画一个名称为Text1的文本框,然后编写以下事件过程:Private Sub Text1_KeyDown(KeyCode As Integer, Shift As Integer) If _________________ Then Text1.SelStart = 0 Text1.SelLength = Len(Text1.Text) End IfEnd Sub要求程序运行时,若输入焦点在Text1上,按下组合键Ctrl+A可以选取Text1内所有的文本,则在横线处应填入的表达式是________。 A: KeyCode = "A" And Shift = "Ctrl" B: KeyCode = 65 And Shift = 2 C: Text1.KeyCode = 65 And Text1.Shift = 2 D: Text1.KeyCode = "A" And Text1.Shift = "Ctrl"

    在窗体上画一个名称为Text1的文本框,然后编写以下事件过程:Private Sub Text1_KeyDown(KeyCode As Integer, Shift As Integer) If _________________ Then Text1.SelStart = 0 Text1.SelLength = Len(Text1.Text) End IfEnd Sub要求程序运行时,若输入焦点在Text1上,按下组合键Ctrl+A可以选取Text1内所有的文本,则在横线处应填入的表达式是________。 A: KeyCode = "A" And Shift = "Ctrl" B: KeyCode = 65 And Shift = 2 C: Text1.KeyCode = 65 And Text1.Shift = 2 D: Text1.KeyCode = "A" And Text1.Shift = "Ctrl"

  • 2022-06-06 问题

    在窗体上画一个名称为Text1的文本框,然后编写以下事件过程:Private Sub Text1_KeyDown(KeyCode As Integer, Shift As Integer) If _________________ Then Text1.SelStart = 0 Text1.SelLength = Len(Text1.Text) End IfEnd Sub要求程序运行时,若输入焦点在Text1上,按下组合键Ctrl+A可以选取Text1内所有的文本,则在横线处应填入的表达式是________。 A: KeyCode = 65 And Shift = 2 B: Text1.KeyCode = "A" And Text1.Shift = "Ctrl" C: KeyCode = "A" And Shift = "Ctrl" D: Text1.KeyCode = 65 And Text1.Shift = 2

    在窗体上画一个名称为Text1的文本框,然后编写以下事件过程:Private Sub Text1_KeyDown(KeyCode As Integer, Shift As Integer) If _________________ Then Text1.SelStart = 0 Text1.SelLength = Len(Text1.Text) End IfEnd Sub要求程序运行时,若输入焦点在Text1上,按下组合键Ctrl+A可以选取Text1内所有的文本,则在横线处应填入的表达式是________。 A: KeyCode = 65 And Shift = 2 B: Text1.KeyCode = "A" And Text1.Shift = "Ctrl" C: KeyCode = "A" And Shift = "Ctrl" D: Text1.KeyCode = 65 And Text1.Shift = 2

  • 2022-05-30 问题

    $\int_{0}^{\frac{\text{ }\!\!\pi\!\!\text{ }}{4}}{[\cos (2t)\mathbf{i}+\sin (2t)\mathbf{j}+t\sin t\mathbf{k}]}\operatorname{dt}=$( ) A: $(\frac{1}{2},\frac{1}{2},\frac{4-\text{ }\!\!\pi\!\!\text{ }}{4\sqrt{2}})$ B: $(1,\frac{1}{2},\frac{4-\text{ }\!\!\pi\!\!\text{ }}{4\sqrt{2}})$ C: $(\frac{1}{2},1,\frac{4-\text{ }\!\!\pi\!\!\text{ }}{4\sqrt{2}})$ D: $(1,1,\frac{4-\text{ }\!\!\pi\!\!\text{ }}{4\sqrt{2}})$

    $\int_{0}^{\frac{\text{ }\!\!\pi\!\!\text{ }}{4}}{[\cos (2t)\mathbf{i}+\sin (2t)\mathbf{j}+t\sin t\mathbf{k}]}\operatorname{dt}=$( ) A: $(\frac{1}{2},\frac{1}{2},\frac{4-\text{ }\!\!\pi\!\!\text{ }}{4\sqrt{2}})$ B: $(1,\frac{1}{2},\frac{4-\text{ }\!\!\pi\!\!\text{ }}{4\sqrt{2}})$ C: $(\frac{1}{2},1,\frac{4-\text{ }\!\!\pi\!\!\text{ }}{4\sqrt{2}})$ D: $(1,1,\frac{4-\text{ }\!\!\pi\!\!\text{ }}{4\sqrt{2}})$

  • 2021-04-14 问题

    Text 1

    Text 1

  • 2022-06-16 问题

    已知齐次方程$(x-1){{y}^{''}}-x{{y}^{'}}+y=0$的通解为$Y={{C}_{1}}x+{{C}_{2}}{{e}^{x}}$,则方程$(x-1){{y}^{''}}-x{{y}^{'}}+y={{(x-1)}^{2}}$的通解是( ) A: ${{\text{C}}_{1}}x+{{\text{C}}_{2}}{{e}^{x}}-({{x}^{2}}+1)$ B: ${{\text{C}}_{1}}x+{{\text{C}}_{2}}{{e}^{x}}-({{x}^{3}}+1)$ C: ${{\text{C}}_{1}}x+{{\text{C}}_{2}}{{e}^{x}}-{{x}^{2}}$ D: ${{\text{C}}_{1}}x+{{\text{C}}_{2}}{{e}^{x}}-{{x}^{2}}+1$

    已知齐次方程$(x-1){{y}^{''}}-x{{y}^{'}}+y=0$的通解为$Y={{C}_{1}}x+{{C}_{2}}{{e}^{x}}$,则方程$(x-1){{y}^{''}}-x{{y}^{'}}+y={{(x-1)}^{2}}$的通解是( ) A: ${{\text{C}}_{1}}x+{{\text{C}}_{2}}{{e}^{x}}-({{x}^{2}}+1)$ B: ${{\text{C}}_{1}}x+{{\text{C}}_{2}}{{e}^{x}}-({{x}^{3}}+1)$ C: ${{\text{C}}_{1}}x+{{\text{C}}_{2}}{{e}^{x}}-{{x}^{2}}$ D: ${{\text{C}}_{1}}x+{{\text{C}}_{2}}{{e}^{x}}-{{x}^{2}}+1$

  • 2022-06-05 问题

    Skim the text and answer the following questions. 1) What type of writing is the text?

    Skim the text and answer the following questions. 1) What type of writing is the text?

  • 2021-04-14 问题

    Part 1 : The text begins with an _________.

    Part 1 : The text begins with an _________.

  • 2022-06-05 问题

    Fast reading text 1

    Fast reading text 1

  • 2022-05-27 问题

    从原点向曲线$$y=1-\ln x$$作切线,则由切线、曲线和$$x$$轴围成图形的面积为(). A: $$\frac{1}{2}{{\text{e}}^{2}}+\text{e}$$ B: $$\frac{1}{2}{{\text{e}}^{2}}-\text{e}$$ C: $${{\text{e}}^{2}}+\text{e}$$ D: $${{\text{e}}^{2}}-\text{e}$$

    从原点向曲线$$y=1-\ln x$$作切线,则由切线、曲线和$$x$$轴围成图形的面积为(). A: $$\frac{1}{2}{{\text{e}}^{2}}+\text{e}$$ B: $$\frac{1}{2}{{\text{e}}^{2}}-\text{e}$$ C: $${{\text{e}}^{2}}+\text{e}$$ D: $${{\text{e}}^{2}}-\text{e}$$

  • 2021-04-14 问题

    函数TEXT("2018/1/1","mm")返回值为1。

    函数TEXT("2018/1/1","mm")返回值为1。

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